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2 years ago

Identify the domain of the function.

Mathematics

1 answer:

RoseWind [281]2 years ago

3 0

Answer:

Domain: All real numbers

Range: y is greater than or equal to -5

Step-by-step explanation:

The domain is every possible x value. Because the function keeps going, it will be all real numbers.

The range is every possible y value. Because the function never goes below -5, y has to be greater than or equal to that.

Hope that helps! :D

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kari74 [83]

Answer: 7 1/2 pounds

Step-by-step explanation:

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2 years ago

. Evaluate each of the following without using a calculator. Show all steps clearly. - 5^2

Verizon [17]

Answer:

Step-by-step explanation:

-5^2 expanded is -5 x -5

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1 year ago

A company logo is shaped like an equilateral triangle with 6-inch long sides. What is the height of the logo? Round to the neare

blondinia [14]

Answer:

5.2 in

Step-by-step explanation:

An equilateral triangle is a triangle with 3 equal sides

Divide the equilateral triangle into two congruent triangles and use Pythagoras theorem to find the height

The Pythagoras theorem : a² + b² = c²

where a = height

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to the nearest tenth = 5.2 in

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6 0

2 years ago

Please help i really need it

masha68 [24]

Answer:

y = 108°

Step-by-step explanation:

Since AB and CD are parallel lines, then

3x - 12 and 2x + 16 are corresponding angles and congruent, thus

3x - 12 = 2x + 16 ( subtract 2x from both sides )

x - 12 = 16 ( add 12 to both sides )

x = 28

Thus

3x - 12 = 3(28) - 12 = 84 - 12 = 72°

y and 3x - 12 are adjacent angles and supplementary, thus

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7 0

3 years ago

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Which of the following equations will produce the graph shown below?

melisa1 [442]

The graph is a circle, centered at the origin, with radius=4.

We know that we can write the equation of a circle with radius r and center (a,b) as :

$(x-a)^2+(y-b)^2=r^2$ .

Thus, substituting (a, b) with (0, 0) and r with 4, we have:

$x^2+y^2=16$ .

The solutions of this equation are all the points forming the circle shown in the picture. The solutions of this equation are still the same even if we multiply both sides of the equation by 2, because rewriting the equation as:

$x^2+y^2=16\\\\x^2+y^2-16=0\\\\2(x^2+y^2-16)=0$ ,

we would still have the same roots.

Thus, the equation of the circle can be written as :

$2x^2+2y^2=32$ .

Answer: B

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3 years ago

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