All categories

4 years ago

Which system of linear inequalities is graphed?

Mathematics

2 answers:

iragen [17]4 years ago

6 0

I am sure that This one would be c

Effectus [21]4 years ago

4 0

I just took the test and the answer is D:

x<-3y

y < -x-1

You might be interested in

Write (2 4) and (6 16) in the form y=mx+b

Lena [83]

Answer:

y = 3x-2

Step-by-step explanation:

We can find the slope using the formula

m = (y2-y1)/(x2-x1)

= (16-4)/(6-2)

=12/4

We then use the point slope form of a line

y-y1= m(x-x1)

y-4 = 3(x-2)

Distribute the 3

y-4= 3x-6

Add 4 to each side

y-4+4 = 3x-6+4

y = 3x-2

This is in slope intercept form

3 0

3 years ago

the cost of four scarves and six hats is 52$. the cost of two hats is$1 more then the cost of one scarf. what are the costs of s

Katena32 [7]

Answer:

is thier anwser chocies?

Step-by-step explanation:

7 0

3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

3 years ago

Solve for x: 3-(2x-5)<-4(x+2)

andriy [413]

3-(2x-5)<-4(x+2)

8-2x<-8-4x

16<-2x

-8 > x. or equivalently x<-8

3 0

4 years ago

Solve this inequality for x 81 -1 1/5r <55

allsm [11]

$81-1\dfrac{1}{5}r < 55\qquad|\text{subtract 81 from both sides}\\\\-\dfrac{1\cdot5+1}{5}r < -26\qquad|\text{change the signs}\\\\\dfrac{6}{5}r > 26\qquad|\text{multiply both sides by 5}\\\\6r > 130\qquad|\text{divide both sides by 6}\\\\r > \dfrac{130}{6}\\\\r > \dfrac{65}{3}\to r > 21\dfrac{2}{3}$

7 0

3 years ago

Read 2 more answers