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weeeeeb [17]
3 years ago
13

What is the area of the trapezoid?

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer: 24

Step-by-step explanation:

Should be 24 if I did the math correctly, I am very sorry if it is wrong.

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Jaylan decided she no longer liked the car she was leasing and turned it in 1
Stolb23 [73]

Answer:

Step-by-step explanation:

I'm pretty sure its lease penalty

5 0
3 years ago
Help on # 2 please. Thank you!
Alenkasestr [34]

Answer:

There are 9 boys in the choir

Step-by-step explanation:

To solve this, create two equivalent fractions with the information given

boys      3         x

------- = ------ = ------

girls       4         12

Then, cross-multiply

4x = 3(12)

4x = 36

x = 9

3 0
4 years ago
PLS HELP DUE TODAY i will give brailest if you show all work please help
Fittoniya [83]

Answer:

15) 3(4+r)=-18

3x4+3xr

12+3r= -18

-12        -12

3r= -30

/3    /3

r= -10

Step-by-step explanation:

distribute the 3 to the 4 and the r you should then have 12+3r=-18 and so subtract from both sides 12 and you should have 3r=-30 divide both sides by 3 and you get your answer r=-10

8 0
3 years ago
Read 2 more answers
S is in the interior of ∠RQT. m∠RQS=(4x-20)°,m∠SQT=(3x+14)°, and m∠RQT=155°
adoni [48]

Step-by-step explanation:

Since we are not told what to look for, we can as well look for the value of x, m∠SQT and  m∠RQS

Given

m∠RQS=(4x-20)°

m∠SQT=(3x+14)°

m∠RQT=155°

The addition postulate is true

m∠RQT= m∠RQS + m∠SQT

Substitute the given parameters into the formula

155 = 4x-20+3x+14

155 = 7x-6

7x = 155+6

7x = 161

x = 161/7

x = 23

Solve for m∠RQS

m∠RQS = 4x-20

m∠RQS = 4(23)-20

m∠RQS = 92-20

m∠RQS = 72°

Solve for m∠SQT

m∠SQT = 3x+14

m∠SQT = 3(23)+14

m∠SQT = 69+14

m∠SQT = 83°

6 0
3 years ago
ASAP!! the density of some steel is 7.85g/cm3. what is the mass of 50g/cm3? give answer to 1 d.p
Elden [556K]

Answer:

D= M/V

7.85= M/50

M= 7.85 x 50

392.5 g

7 0
3 years ago
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