The G.C.F of the given algebraic expression is; ⁴⁹/₆a xy
<h3>What is the G.C.F (Greatest Common Factor)?</h3>
The greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 the GCF = 6.
We are given the algebraic expression;
(3 x y * 4x²y * ¹/₁ * 5x³y ^ z * 4)7a * 1/1 * 7*6
Expanding this further gives;
⁴⁹/₆a((3xy * 4x²y * 20x³y ^ z )
Now, the GCF of the terms inside the bracket would be x y. Thus, expanding the GCF we have;
⁴⁹/₆a xy((3 * 4x * 20x²y^(z - 1))
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It would be 100 because 360-60=300 then 300 divided by 3 equals 100
Note that if
, then
, and so we can collapse the system of ODEs into a linear ODE:
which is a pretty standard linear ODE with constant coefficients. We have characteristic equation
so that the characteristic solution is
Now let's suppose the particular solution is
. Then
and so
Thus the general solution for
is
and you can find the solution
by simply differentiating
.
Answer:
a) 5765760
b) 60480
c) 5705280
Step-by-step explanation:
Assuming that order is not important:
Number of women = 7
Number of men = 9
Members of the delegation = 6
a) How many delegations are possible?
b) How many of these delegations have all men?
c) How many of these delegations have at least one woman?
Answer:
The records can be select in 332,640 ways.
Step-by-step explanation:
Consider the provided information.
There are 11 records to select from and a disc jokey can play 6 records.
Here, we need to find the number of permutation of n = 11 records taken r = 6 at a time.
Use the formula:
Substitute the respective values in the above formula.
Hence, the records can be select in 332,640 ways.