Answer:
A) JK and AB =
![[tex] \boxed{( \theta) = \f{12}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%5Cf%7B12%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, =》 
=》 
[/tex]
B) AABC
![[tex] \boxed{( \theta) = {1}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%7B1%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, 
C) AABM:
![[tex] e \fbox{: }](https://tex.z-dn.net/?f=%5Btex%5D%20e%20%5Cfbox%7B%3A%20%7D)
The value of k for which 
is 
ans[/tex]
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Function notation<span> is the way a </span>function<span> is written. It is meant to be a precise way of giving information about </span><span /><span>the</span>function<span> without a rather lengthy writtern</span>
Answer:
Step-by-step explanation:
20 oz walnuts = 20/25 = 0.8 ounces of walnuts per bag. / bag
11.2 oz of almonds = 11.2 / 25 = 0.448 ounces of almonds / bag
28.3 oz of cashews = 28.3 / 25 = 1.132 oz of cashews / bag
Answer:
the polygon on the right side is doubled the size of the one on the left, therefore x=11
y=4x+2. eq1
y=5x. eq2
4x=2-y
x=(2-y) /4
substitute in equation 2
y=5(2-y) /2
y=(10-5y)/2
4y=10-5y
9y=10
y=10/9
substitute in equation 2 or 1
substituting in equation 2
10/9=5x
x=10/45
x=10/45 y=10/9
you can verify it also.
HOPE IT HELPS!!
