All categories

3 years ago

Find the value of x. Round to the nearest tenth. X 12 x = [?]

Mathematics

1 answer:

DiKsa [7]3 years ago

8 0

Answer:

63.4

Step-by-step explanation:

Tan = opposite/adjacent

Tan x = tan-1

Tan-1 (6/12)

=63.43494882

63.4

You might be interested in

A line with a slope of 0 passes through the point (10, 6). What is its equation in slope-intercept form?

qaws [65]

Answer:

The slope is 0, then the line is horizontal.

y = 6

Step-by-step explanation:

6 0

2 years ago

M∠Q = m∠R = m∠S = 40 POINTS!!!!!!!

Marizza181 [45]

9514 1404 393

Answer:

∠Q = 89°

∠R = 123°

∠S = 91°

Step-by-step explanation:

It seems easiest to start by finding the measures of each of the arcs. The measure of an arc is double the measure of the inscribed angle it subtends.

arc QRS = 2·∠P = 114°

So, ...

arc QR = arc QRS - arc RS = 114° -41° = 73°

The total of the arcs around the circle is 360°, so ...

arc PQ = 360° -arc PS -arc QRS

arc PQ = 360° -137° -114° = 109°

∠Q = (1/2)(arc RS + arc PS) = (1/2)(41° +137°)

∠Q = 89°

∠R = (1/2)(arc PS +arc PQ) = (1/2)(137° +109°)

∠R = 123°

∠S = (1/2)(arc PQ +arc QR) = (1/2)(109° +73°)

∠S = 91°

7 0

3 years ago

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui

Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= $\frac{dx}{dt}=1. 8 m/s$

$\triangle ABD\sim\triangle ECD$

Therefore, $\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{y}{2}=\frac{12}{x}$

$xy=24$

Differentiate w.r.t t

$x\frac{dy}{dt}+y\frac{dx}{dt}=0$

$x\frac{dy}{dt}=-y\frac{dx}{dt}$

$\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}$

When the man is 4 m from the building

Then, we have x=12-4=8 m

$\frac{dx}{dt}=1.8 m/s$

Substitute the values in above equation then, we get

$8y=24$

$y=\frac{24}{8}=3$

Substitute the values then we get

$\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s$

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0

3 years ago

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

Alex73 [517]

The solution is 25% acid, which means 2.5 liters acid (10 x .25).
you need that 2.5 liters to be 10%, or 1/10th the total. 
the total would have to be 25 liters (2.5 x 10) so when you add to 10 to get 25 you get 15 liters. Hope I helped!

3 0

3 years ago

Read 2 more answers

Are the given ratios equivalent Explan why or why not 3 : 5 12 : 20

sasho [114]

Yes you take 3 times 4 and receive 12 and 5 times 4 and receive 20

4 0

3 years ago