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PtichkaEL [24]
3 years ago
5

Find the value of x. Round to the nearest tenth. X 12 x = [?]

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0

Answer:

63.4

Step-by-step explanation:

Tan = opposite/adjacent

Tan x = tan-1

Tan-1 (6/12)

=63.43494882

63.4

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What’s is the slope of the lin
Lady bird [3.3K]

Answer:

1/3

Step-by-step explanation:

<em>Method 1.</em>

slope = rise/run

Rise is vertical distance.

Run is horizontal distance.

Find two points that are easy to read (on grid intersections):

(2, -1) and (5, 0).

Start at (2, 1). You need to go to (5, 0) by moving only vertically and horizontally. Go up 1 unit. That is a rise of 1. Now go right 3 units. That is a run of 3.

rise = 1

run = 3

slope = rise/run = 1/3

<em>Method 2.</em>

Use the slope formula and two points on the line.

slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}

Use points (2, -1) and (5, 0).

slope = m = \dfrac{0 - (-1)}{5 - 2}

slope = m = \dfrac{0 + 1}{3}

slope = m = \dfrac{1}{3}

slope = 1/3

8 0
3 years ago
ou earn $17.50/hr and work 40 hr/wk. Your deductions are FICA (7.65%), federal tax withholding (12.3%), and state tax withholdin
fgiga [73]

Step-by-step explanation:

MARK A BRAINLESS THIS ANSWER IS CORRECT

6 0
2 years ago
For each expression, write an equivalent expression by applying the distributive
Semenov [28]
The answer is 2x-10.

(x-5)2
=(x+-5)(2)
=(x)(2)+(-5)(2)
=2x-10
7 0
3 years ago
Construct a 99% confidthence interval for the population mean .Assume the population has a normal distribution. A group of 19 ra
Kobotan [32]
<h2>Answer with explanation:</h2>

Confidence interval for mean, when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n= sample size

s= sample standard deviation

t_{\alpha/2} = Critical t-value for n-1 degrees of freedom

We assume the population has a normal distribution.

Given, n= 19 , s= 3.8 , \overline{x}=22.4

\alpha=1-0.99=0.01

A) Critical t value for \alpha/2=0.005 and degree of 18 freedom

t_{\alpha/2} = 2.8784

B) Required confidence interval:

22.4\pm ( 2.8744)\dfrac{3.8}{\sqrt{19}}\\\\=22.4\pm2.5058\\\\=(22.4-2.5058,\ 22.4+2.5058)=(19.8942,\ 24.9058)\approx(19.9,\ 24.9)

Lower bound = 19.9 years

Uppen bound = 24.9 years

C) Interpretation: We are 99% confident that the true population mean of lies in (19.9, 24.9) .

5 0
3 years ago
What is the value of x , when X squared +5=21
notsponge [240]

Answer:

x=4

Step-by-step explanation:

4^2=16

16+5=21

8 0
3 years ago
Read 2 more answers
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