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Vilka [71]
3 years ago
7

Exponential function

Mathematics
2 answers:
Alina [70]3 years ago
8 0
F(x) = -4 * 2^(1-x)
f(x) = -4 * 2^1 / 2^x
f(x) = -8 / 2^x
f(x) = -8 (1/ 2)^x

answer is B. 
f(x) = -8 (1/ 2)^x

Romashka [77]3 years ago
6 0
We can break the term 2^{1-x} apart using the following law of exponents:

a^{x+y}=a^xa^y

Applying that, we find that

2^{1-x}=2^{1+(-x)}=2^1\cdot2^{-x}=2\cdot \frac{1}{2^x}

Substituting that into our original function, we have

f(x)=-4\cdot2^{1-x}\\
f(x)=-4\cdot2\cdot \frac{1}{2^x}

Which we can rewrite in the form f(x)=ab^x as

f(x)=-8\cdot\big( \frac{1}{2}\big)^x
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