A b + a c - 4 b - 4 c = a ( b + c ) - 4 ( b + c ) =
= (b + c) (a - 4)
Answer:
Step-by-step explanation:
→ Find the LCM of the denominators (2,4 and 8)
LCM = 8
→ Multiply the whole equation by 8 to get rid of the fractions
4x + 6 = 7
→ Minus 6 from both sides to isolate 4x
4x = 1
→ Divide both sides by 4 to isolate x
Answer:
(-2, -8)
x = -2
y = -8
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
13x - 6y = 22
x = y + 6
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 13(y + 6) - 6y = 22
- Distribute 13: 13y + 78 - 6y = 22
- Combine like terms: 7y + 78 = 22
- Isolate <em>y</em> term: 7y = -56
- Isolate <em>y</em>: y = -8
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = y + 6
- Substitute in <em>y</em>: x = -8 + 6
- Add: x = -2
The principal, real, root of:
![\sqrt[2]{55}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B55%7D)
=7.41619849
