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Stels [109]
2 years ago
10

Help! Equivalent expressions (7th grade) match the ones that go are equivalent. Each expression can only be used once

Mathematics
1 answer:
Sedaia [141]2 years ago
4 0

Answer:

Step-by-step explanation:

Combine your like terms https://www.mathpapa.com/algebra-calculator.html

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Solve the system.<br><br> 4x+2y+3z=12<br> 2x−3y+5z=−7<br> 6x−y+4z=−3
Vikki [24]
Are these 3 separate questions?
4 0
3 years ago
How many zeros are there behind 35!<br> (50 points)
Romashka [77]

Answer:

4

Step-by-step explanation:

30, 20, 10, 0, and I oop...

6 0
3 years ago
Solve the following system of equations: 3x − 2y = 6 6x − 4y = 12 (0, 0) (6, 12) Infinitely many solutions No solutions
Fantom [35]

<u>Answer:</u>

The correct answer option is: infinitely many solutions.

<u>Step-by-step explanation:</u>

We are given the following system of equations:

3 x - 2 y = 6 --- (1)

6 x - 4 y = 1 2 --- (2)

Dividing equation (2) by 2 to get:

3 x - 2 y = 6 --- (3)

As the equation (3) is same as the equation (1), therefore the system will have infinitely many solutions.

7 0
3 years ago
Read 2 more answers
How many numbers between 1 and 100 (inclusive) are divisible by 4 or 5
BaLLatris [955]

Answer: 40 numbers

Step-by-step explanation:

For us to do this, we will have to group the numbers in groups of 20.

You should note that from 1 to 20, there are 5 numbers that are divisible by 4 which are 4, 8, 12, 16, 20.

Also, there are 5 "20s" that are in 100, therefore 5 X 5 = 25 numbers that are divisible by 4.

Likewise, there are also 4 numbers that are divisible by 5 which are 5 , 10 , 15 , 20.

There are also 5 "20s" in 100, thos will give 5 x 4 = 20 numbers that are divsible by 5.

However, we have to subtract the numbers that are divisible by both 4 and 5 in order to prevent double counting.

These are 20, 40, 60, 80 and 100.

Thereforee, we will have:

25 + 20 - 5 = 40 numbers that are divisible by 4 or 5 from 1-100.

6 0
3 years ago
What is the smallest, positive integer value of x such that the value of f(x) = 2x + 3 exceeds the value of g(x) = 50x + 5?
weeeeeb [17]
F(x) > g(x)
2^x + 3 > 50x + 5

for x = 3 , f(3) > g(3)
11 > 155 (false)

for x = 10 , f(10) > g(10)
1027 > 505 (true)

for x = 9 , f(9) > g(9)
515 > 455 (true)

for x = 8 , f(8) > g(8)
259 > 405 (false)

the smallest,positive integer value of x is 9 since the value of 9 is the last number to exceeds g(x)
7 0
3 years ago
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