Deijah has $6.25.
Now, this 6.25 is comprised of 0.05s and 0.25s.
We know that there are 12 0.25s.
We now want to know how many remaining 0.05s there are.
Again, we know that the number of 0.05s he has, which is 12, multiplied by 0.05, plus the number of 0.25s he has, multiplied by 0.25, equals 6.25.
Thus, the answer is A, 0.25 x 12 + 0.05 x n = 6.25.
Answer:
1036 students
Step-by-step explanation:
Let the number of students at West High be "w" and the number of students at East High be "e"
West High population is 250 FEWER than TWICE of East High, we can write:
w = 2e - 250
Total students in both schools is 2858, so we can write 2nd equation as:
e + w = 2858
We can replace 1st equation in 2nd to get an equation in e, and find "e":
e + w = 2858
e + (2e - 250) = 2858
3e - 250 = 2858
3e = 2858 + 250
3e = 3108
e = 3108/3
e = 1036
Hence,
number of students attending East High School = 1036 students
It would end up being 1.50 at the end of the day
Answer:
L = 18 and w = 16
Step-by-step explanation:
The area of a rectangle is found by A = l*w. Since the length here is 2 more than the width or 2 + w and the width is w, substitute these values and A = 288 to solve for w.
To solve for w, move 288 to the other side by subtraction. Then factor and solve.
Set each factor equal to 0 and solve.
w - 16 = 0 so w = 16
w + 18 = 0 so w = -18
Since w is a side length and length/distance cannot be negative, then w = 16 is the width of the rectangle.
This means the length is 16 + 2 = 18.
13.33% is your answer
hope this helps :D
put the repeating sign over the last 3
