Answer:
Hope the pictures will help you..
Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
Answer:
x(3 – 4)
Step-by-step explanation:
x^3y
/x^4y
get rid of y
x^3/x^4
subtract exponents
x(3 – 4)
Brainliest please ask me if you have more questions.
the simple interest is granted by the end of the year probably.If in 1/2 a year he gathered $115.50 then
115.50=3.300×r/2
r=231/3300
r=7%