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Alexus [3.1K]
3 years ago
14

A teacher divided students into groups of 3. Each group of 3 wrote a report that had 9 pictures in it. The students used 585 pic

tures altogether. How many students were there in all?
Mathematics
2 answers:
jeyben [28]3 years ago
5 0
So this is what i did but im not sure if its 100% correct

585 / 9 to get the number of groups = 65

then you take 65 x 3 for number of students in each group and you get the final answer of 195 students
Marrrta [24]3 years ago
3 0

Answer:

195 students.

Step-by-step explanation:

Each group of three created (or used) 9 pictures.

So that means three pictures per student.

Dividing 585 students by 3 pictures per student means that there are

585/3 = 195 students.

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$16.20

Step-by-step explanation:

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Answer:

A = 153.94 sq mi

Step-by-step explanation:

In this scenario, we would be starting from the center point and searching the area of a square since the distance in every direction would the same 7 mi. This 7-mile distance would be our radius in this scenario. We now need to use the formula for the Area of a circle to calculate the search area. This formula is the following

A = \pi r^{2}

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3 years ago
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fenix001 [56]

Answer:

first y=|x+6|

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Step-by-step explanation:

first y=|x+6|

y=2x+7,y=2x-7 parallel lines

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4 years ago
PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!
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Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

  • \cos{\theta} = \pm \frac{2\sqrt{2}}{3}
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<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

Hence, applying the identity, the cosine is given as follows:

\cos^2{\theta} = 1 - \sin^2{\theta}

\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2

\cos^2{\theta} = 1 - \frac{1}{9}

\cos^2{\theta} = \frac{8}{9}

\cos{\theta} = \pm \sqrt{\frac{8}{9}}

\cos{\theta} = \pm \frac{2\sqrt{2}}{3}

The tangent is given by the sine divided by the cosine, hence:

\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}

\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}

\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

\tan{\theta} = \pm \frac{\sqrt{2}}{4}

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

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Answer:

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