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morpeh [17]
3 years ago
5

Help need this answer as as possible

Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

15.5

Step-by-step explanation:

I can help with this. He doesn't tell how many dollars she earned from her dad but tells you what is left. So we add 13.73 + 1.77

We add because She used to spend it and because she only gave us what was left. We want to push it to what it was before so we do the opposite.

13.73 + 1.77 = 15.5

I am not really sure of what the words are on the last part but i think u can figure it out. My answer is 15.5 but if you aren't asking for this just ignore it.

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Item: c = p(1 + ). What is the final cost of a $40 item after an 8% tax is applied?
Snowcat [4.5K]

40(0.08) = 3.2

3.2+40

Answer: 43.20

5 0
3 years ago
3. If x +4, 2x+5, and 4x +3 represent the first three terms of an arithmetic sequence, then find the
solong [7]

first term = initial number

second term = initial number + common difference

third term = initial number + 2(common difference)

So...

2x+5-(x+4) = common difference

4x+3-(2x+5) = also common difference

2x+5-(x+4) = x+1

4x+3-(2x+5) = 2x-2

Because x+1=2x-2 we can solve for x.

x=3

So the sequence goes... 7,11,15...

19 is the fourth term

8 0
2 years ago
Y=3/2x+6 parallel to (-2 -4)
Aleonysh [2.5K]

Answer:

no it's not parallel to that.

4 0
2 years ago
Determine the discriminant for the quadratic equation 0=-2x2+3. Based on the discriminant value, how many real number solutions
Arlecino [84]

The discriminant of 0 = -2x^2 + 3 is 24 and it has 2 real solutions

<h3>How to interpret the discriminant?</h3>

The equation is given as:

0 = -2x^2 + 3

Rewrite as:

-2x^2 + 3 = 0

The discriminant of an equation is calculated using:

D = B^2 - 4AC

In this case, we have:

A = -2

B = 0

C = 3

So, we have:

D = (0)^2 - 4 * -2 * 3

Evaluate

D = 24

When the discriminant is 0 or more, then the equation has real roots

Hence, the discriminant of 0 = -2x^2 + 3 is 24 and it has 2 real solutions

Read more about quadratic functions at:

brainly.com/question/1214333

#SPJ1

6 0
2 years ago
a radioactive substance has a Decay rate of 5% per hour. if 500 hundred grams are present initially, how much of the substance r
kirza4 [7]
First we have to calculate the half-life
half-life = elapsed time * log (2) / log (bgn amt / end amt)
half-life = 1 hour * 0.30102999566 / log (1 / .95)
half-life = 0.30102999566 / log (<span> <span> <span> 1.0526315789 )
</span> </span> </span>half-life = 0.30102999566 / 0.022276394692
half-life = <span> <span> <span> 13.5134073454 hours
</span> </span> </span>
Ending Amount = Beginning Amount / 2^n
Where "n" = number of half-lives
For 4 hours, "n" equals
4 / 13.5134073454
=<span> <span> <span> 0.2960023255

</span></span></span>Ending Amount = 500 grams / 2^.2960023255
Ending Amount = 500 grams /<span> <span> <span> 1.2277376629
</span> </span> </span>Ending Amount = <span> <span> <span> 407.2531250707 grams

Source:
http://www.1728.org/halflife.htm


</span></span></span>
3 0
3 years ago
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