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8_murik_8 [283]
3 years ago
8

  a right triangle has a hypotenuse that is 30 inches and a leg that is 15 inches. what is the length of the other leg rounded t

o the nearest whole number? 
a.26 inches
b.675 inches
c.15 inches
d.4 inches​
Mathematics
2 answers:
Damm [24]3 years ago
5 0
The answer is 26 inches
Katen [24]3 years ago
3 0

Answer:A

Step-by-step explanation: divide 40 and 15 and round it to the nearest 10

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HELP PLEASE! Find the standard deviation for Data set 1 and 2. round to the nearest hundred. DATA SET ONE: 8.2, 11.6 8.7, 10.6,
Elan Coil [88]

Answer:

0.92 and 1.25 respectively

Step-by-step explanation:

0.92 and 1.25 respectively

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standard deviation = square root of the mean deviation of each value

then deduct the mean from each element

and square each value and add them together. not you should square each deviation value before you add them

at last divide the result by the number of frequency and find it's square root

3 0
3 years ago
5/12=10/? Someone please help
nasty-shy [4]

Answer:

0.4167

Step-by-step explanation:

hope i help

4 0
2 years ago
Read 2 more answers
Determine the sum of the first 9 terms in the geometric series where r= -0.25 and a1= 256.
Damm [24]

\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ r=-0.25\\ a_1=256\\ n=9 \end{cases}

\bf S_9=256\left(\cfrac{1-(-0.25)^9}{1-(-0.25)}  \right)\implies S_9=256\left( \cfrac{1+0.25^9}{1+0.25} \right) \\\\\\ S_9=256\left(  \cfrac{52429}{65536}\right)\implies S_9=\cfrac{52429}{256}\implies S_9=204.80078125

4 0
2 years ago
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What additional information is needed to prove the triangles are congruent by the SAS Prostulate
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It is that the angle has to be formed by two pairs of congruent/corresponding sides of the triangle
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2 years ago
(1) Cos AcosecA=cot A​
Mashutka [201]

Answer:

The Basic Identities are :

cosec(A) =  \frac{1}{ \sin(A) }

\tan(A)  =  \frac{ \sin(A) }{ \cos(A) }

\cot(A)  =  \frac{1}{ \tan(A) }  =  \frac{ \cos(A) }{ \sin(A) }

So for this question :

\cos(A)cosec(A) =  \cot(A)

l.s.h =  \cos(A)  \times  \frac{1}{ \sin(A) }

l.s.h =  \frac{ \cos(A) }{ \sin(A) }

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7 0
3 years ago
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