Ask question

Ask question

All categories

3 years ago

10

The weights for newborn babies is approximately normally distributed with a mean of 5.4 pounds and a standard deviation of 1.8 p

ounds. Consider a group of 1500 newborn babies: 1. How many would you expect to weigh between 3 and 6 pounds

1 answer:

Mariana [72]3 years ago

6 0

Answer:

You would expect 807 babies to weigh between 3 and 6 pounds.

Step-by-step explanation:

We are given that

Mean, $\mu=5.4$ pounds

Standard deviation, $\sigma=1.8$ pounds

n=1500

We have to find how many would you expect to weigh between 3 and 6 pounds.

The weights for newborn babies is approximately normally distributed.

Now,

$P(3$

$=P(-1.33$

$P(3$

$P(3$

$P(3$

Number of newborn babies expect to weigh between 3 and 6 pounds

= $1500\times 0.538=807$

You might be interested in

What is the distance between the points (2, 1) and (14, 6) on a coordinate

ipn [44]

Answer: 13 units

Step-by-step explanation:

6 0

3 years ago

A sample of restaurants in a city shows that the average cost of an appetizer is $6.32 with a standard deviation of

iren2701 [21]

The answer would be b

6 0

3 years ago

Two perpendicular lines intersect at the origin. If the slope of the first line is 3, what is the equation of the second line?.

tester [92]

If slope of first line is 3 and is perpendicular to second line
then second line has a slope of -1/3

5 0

3 years ago

Read 2 more answers

You borrow $1000 at 6% simple interest for a year how much do you have to pay back?

Rainbow [258]

Answer:150

Step-by-step explanation:

So every year the interest will be $1000 * 5 / 100 = $50. That is, after 3 years 3 * $50 = $ 150. Simple interest does not take into account the reduction of the principal but calculates the interest over the same initial amount, in this case $1000. So, the answer is $150, which is the result of $50 times 3.

4 0

3 years ago

The average lifetime of a certain new cell phone is 3.4 years. The manufacturer will replace any cell phone failing within three

melisa1 [442]

Answer:

68% of these phones last 3.87 years.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The average lifetime of a certain new cell phone is 3.4 years.

This means that $m = 3.4, \mu = \frac{1}{3.4} = 0.2941$

So

$P(X \leq x) = 1 - e^{-0.2941x}$

68% of these phones last how long (in years)?

This is x for which:

$P(X \leq x) = 0.68$

$P(X \leq x) = 1 - e^{-0.2941x}$

Then

$0.68 = 1 - e^{-0.2941x}$

$e{-0.2941x} = 0.32$

$\ln{e{-0.2941x}} = \ln{0.32}$

$-0.2941x = \ln{0.32}$

$x = -\frac{\ln{0.32}}{0.2941}$

$x = 3.87$

68% of these phones last 3.87 years.

4 0

3 years ago