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Sergio039 [100]
2 years ago
13

Pls pls help i will give brainliest

Mathematics
1 answer:
Luba_88 [7]2 years ago
3 0

Answer:

give me a brainliest now

Step-by-step explanation:

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For what value of x will the function f(x) = -3(x - 10)(x - 4) have a maximum value? Find the maximum value.
gayaneshka [121]

Hello!

To find the maximum value of the function f(x) = -3(x - 10)(x - 4), the easiest way is to find the vertex using the formula: x = -b/2a.

Firstly, we need to simplify f(x).

f(x) = -3(x - 10)(x - 4)

f(x) = -3(x² - 14x + 40)

f(x) = -3x² + 42x + -120

Since the equation f(x) is now simplified to standard form, we can find the vertex.

a = -3, b = 42, and c = -120

x = -(42)/2(-3) = -42/-6 = 7

Then, we substitute 7 into the the function f(x) = -3(x - 10)(x - 4), or

f(x) = -3x² + 42x + -120, to find the y-value of the vertex.

f(x) = -3(7 - 10)(7 - 4)

f(x) = -3(-3)(4)

f(x) = 27

The vertex of f(x) is (7, 27).

Therefore, the maximum x-value for the function f(x) is 7.

4 0
3 years ago
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Express your answer in scientific notation. <img src="https://tex.z-dn.net/?f=3600%20-%206.3%5Ccdot%2010%5E%7B2%7D" id="TexFormu
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Evaluate the power 3600-6.3 x 100, then your gonna want to multiply the numbers 3600-630 , once you subtract the numbers your answer will be 2970
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I need help ASAP !!!!!!!!!
antiseptic1488 [7]

the anser would be great to have a male or female plastic surgery and then you can get a chance to win the game is to be like that in mind that I have to be high as a kite to get the best way for me to do with my friends and family

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3 years ago
In ΔQRS, s = 2.3 inches, ∠S=51° and ∠Q=44°. Find the area of ΔQRS, to the nearest 10th of an square inch.
postnew [5]

Answer:

Area of ΔQRS = 2.3 square inches

Step-by-step explanation:

From the given information,

<S + <Q + <R = 180^{o}

51 + 44 + <R = 180^{o}

95 + <R = 180^{o}

<R = 180^{o} - 95

    = 85^{o}

<R = 85^{o}

Applying the Sine rule, we have;

\frac{q}{SinQ} = \frac{r}{SinR} = \frac{s}{SinS}

Using \frac{r}{SinR} = \frac{s}{SinS}

\frac{r}{Sin 85} = \frac{2.3}{Sin51}

r = \frac{2.3*Sin85}{sin51}

  = 2.9483

r = 2.9 inches

Also, \frac{q}{SinQ} = \frac{s}{SinS}

\frac{q}{Sin44} = \frac{2.3}{Sin51}

q = \frac{2.3*Sin44}{Sin51}

  = 2.0559

q = 2.0 inches

From Herons formula,

Area of a triangle = \sqrt{s(s-q)(s-r)(s-s)}

s = \frac{2.3 + 2.0 + 2.9}{2}

  = 3.6

Area of ΔQRS = \sqrt{3.6(3.6-2.0(3.6-2.9)(3.6-2.3)}

                        = 2.2895

Area of ΔQRS = 2.3 square inches

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Answer:

(-1, 0.5)

Step-by-step explanation:

please mark brainliest

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