Answer:
The two iterations of f(x) = 1.5598
Step-by-step explanation:
If we apply Newton's iterations method, we get a new guess of a zero of a function, f(x), xₙ₊₁, using a previous guess of, xₙ.
xₙ₊₁ = xₙ - f(xₙ) / f'(xₙ)
Given;
f(xₙ) = cos x, then f'(xₙ) = - sin x
cos x / - sin x = -cot x
substitute in "-cot x" into the equation
xₙ₊₁ = xₙ - (- cot x)
xₙ₊₁ = xₙ + cot x
x₁ = 0.7
first iteration
x₂ = 0.7 + cot (0.7)
x₂ = 0.7 + 1.18724
x₂ = 1.88724
second iteration
x₃ = 1.88724 + cot (1.88724)
x₃ = 1.88724 - 0.32744
x₃ = 1.5598
To four decimal places = 1.5598
A circle with center 
and radius 
has equation
If we substitute 
in this equation, we have
This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:
The expression simplifies to
The solutions to the associated equation are
So, the parabola is negative between the two solutions:
Answer:
n = (1/2)(-1 ± i√2)
Step-by-step explanation:
Among the several ways in which quadratic equations can be solved is the quadratic formula. Putting to use the coefficients {12, 12, 9}, we obtain the discriminant, b^2 - 4ac: 12^2 - 4(12)(9) = 144 - 432 = -288. The negative sign of this discriminant tells us that the quadratic has two unequal, complex roots. These roots are:
-b ± √(discriminant)
n = ---------------------------------
2a
Here we have:
-12 ± √(-288) -12 ± i√2√144 -12 ± i12√2
n = ---------------------- = ------------------------ = --------------------
2(12) 24 24
or:
n = (1/2)(-1 ± i√2)
Answer:
i also need
Step-by-step explanation:
