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kap26 [50]
3 years ago
11

Are two regular hexagons always congruent?

Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

Polygons - Hexagons. So, the sum of the interior angles of a hexagon is 720 degrees. All sides are the same length (congruent) and all interior angles are the same size (congruent).

Step-by-step explanation:

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A map has a scale of 1/8 of an inch is equal to 1/4 of a mile. What is the unit rate of inches per mile
algol [13]

Answer:

1 inch per 2 miles.

Step-by-step explanation:

1/8 of an inch = 1/4 of a mile.

To solve the rate of inch per mile, multiply 8 to both sides (to make inch = 1)

(1/8)(8) = 1

(1/4)(8) = 8/4 = 2

The unit rate of inches per mile is 1 inch per 2 miles.

~

6 0
3 years ago
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
3 years ago
Help me plsssszzzzzzzzzzzzzzzzzzz​
OlgaM077 [116]
Use the formula 1/2•b•h to find your answer
5 0
3 years ago
4
Ira Lisetskai [31]

Answer:

∠MLP = 72° ,           ∠LJK = 22° ,            ∠JKL = 72° ,          ∠KLJ  =  86°

Step-by-step explanation:

Here, given In ΔJLK and  ΔMLP

Here,  JK  II  ML,  LM = MP

∠JLM = 22° and  ∠LMP = 36°

Now, As angles opposite to equal sides are equal.

⇒ ∠MLP = ∠MPL  = x°

Now, in  ΔMLP

By <u>ANGLE SUM PROPERTY</u>:   ∠MLP + ∠MPL  + ∠LMP = 180°

⇒ x° + x° + 36° = 180°

⇒ 2 x  = 180 - 36 = 144

or, x  = 72°

⇒ ∠MLP = ∠MPL  = 72°

Now,as  JK  II  ML

⇒ ∠LJK = ∠JLM = 22° ( Alternate pair of angles)

Now, by the measure of straight angle:

∠MLP + ∠JLM + ∠JLK = 180°  ( Straight angle)

⇒ 72° + 22° + ∠JLK = 180°

or, ∠JLK  =  86°

In , in  ΔJLK

By <u>ANGLE SUM PROPERTY</u>:   ∠JKL + ∠JLK  + ∠LJK = 180°

⇒  ∠JKL + 86° + 22° = 180°

⇒ ∠JKL   = 180 - 108 = 72 , or ∠JKL = 72°

Hence, from  above proof ,  ∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° ,

∠KLJ  =  86°

7 0
3 years ago
you invest $1000 dollars in an account at 2.5% per year simple interest. How much will you have in the account at the beginning
Lina20 [59]
<span>I = PRT

</span><span>P = 1000
R = 2.5% -- change to a decimal = .025
T = 3
</span>
<span> now we sub I = PRT
I = (1000)(.025)(3)
I = 75
</span><span> so at the end of 3 years, there will be : 1000 + 75 = $ 1075 in the account
</span>
Hope this helps!!
~Lena~
<span />
7 0
4 years ago
Read 2 more answers
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