Please help ASAP!!!!

Mathematics

2 answers:

katrin [286]3 years ago

6 0

The answer is B i had this problem.

Ira Lisetskai [31]3 years ago

3 0

Answer: OPTION B

Step-by-step explanation:

Multiply both denominators to find the Least Common Denominator:

$LCD=(3y-4)(y^2)$

Now, divide each original denominator by the LCD and multiply the result by each numerator. Then:

$=\frac{(6y^2+2y)(y^2)-(9y-7)(3y-4)}{(3y-4)(y^2)}$

Applying Distributive property, you get:

$=\frac{6y^4+2y^3-(27y^2-36y-21y+28)}{3y^3-4y^2}\\\\=\frac{6y^4+2y^3-27y^2+36y+21y-28}{3y^3-4y^2}$

Add the like terms in the numerator:

$=\frac{6y^4+2y^3-27y^2+57y-28}{3y^3-4y^2}$

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Use completing the square to solve for x in the equation (x-12)(x+4)=9.

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We then factor like a perfect square trinomial and simplify.

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