Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
just count how many there and and eliminate one by one
Answer:
50
Step-by-step explanation:
Use this equation
where b is arc VY, A is arc XV.
Substitute the equation in
so our arc measure is 50
50-8=42(half of his score)
42*2=84(whole score)
s=84
Answer:
a) 23.5619449 m^2 b) 351.8583772 cm^2 c) 75.39822369 cm^2
Step-by-step explanation:
a):
SA = 2πr^2+2πr
r= 3/2 = 1.5
SA= 2π*1.5^2 + 2π*1.5
SA= 15/2 ∏
SA= 23.5619449 m^2 round it as you want
b): Same steps as "a" but rather than m^2 it is cm^2
the answer will be:
SA= 112π
SA= 351.8583772 cm^2 round it as you want
c): the radius is already given so just place it in place of r
SA= 2π*3^2 + 2π*3
SA= 24π
SA= 75.39822369 cm^2
