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2 years ago

Suppose 8x + 16 ice cream cones

Mathematics

1 answer:

kvv77 [185]2 years ago

8 0

Answer:

B. 152 + 7

Step-by-step explanation:

(8x + 16) + (7x - 9)

8x + 16 + 7x - 9

15x + 16 - 9

15x + 7

None of these options have this answer, so we see A and B:

A. x + 7

B. 152 + 7

It can't be A because we have 15x and A is x + 7

By process of elimination we have B. 152 + 7

x = 10 and 2/15

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Xelga [282]

Answer:

X= -3

Step-by-step explanation:

3x-9=8x+6

3x-8x=6=9

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What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

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Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

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in this problem we have

$2x^2+7x+4=0$

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substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

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$x=\frac{-7+\sqrt{17}} {4}$

and

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2 years ago

I need help here is the problem

leva [86]

Answer:

12.96pi

Step-by-step explanation:

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nikitadnepr [17]

Answer: $A_2=\frac{\pi(2D)^{2}}{4}$

Step-by-step explanation:

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Answer:

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