Answer:Orbital period =21.22hrs
Explanation:
given that
mass of earth M = 5.97 x 10^24 kg
radius of a satellite's orbit, R= earth's radius + height of the satellite
6.38X 10^6 + 3.25 X10^7 m =3.89 X 10^7m
Speed of satellite, v= 
where G = 6.673 x 10-11 N m2/kg2
V= \sqrt (6.673x10^-11 x 5.97x10^ 24)/(3.89 X 10^ 7m)
V =10,241082.2
v= 3,200.2m/s
a) Orbital period
= 
V=
T= 2 
r/ V
= 2 X 3.142 X 3.89 X 10^7m/ 3,200.2m/s
=76,385.1 s
60 sec= 1min
60mins = 1hr
76,385.1s =hr
76,385.1/3600=21.22hrs
Answer:
The potential energy of the ball is 784 joules. And the kinetic energy of it is 392 while falling halfway down.
Explanation:
PE = mass (2kg) * Gravitational acceleration (9.8 m/s^2)* height (40 meters)
KE = 1/2 mass (1 kg) * velocity^2 (19.8)
For this problem, we are asked to calculate for the distance traveled. We set up the equations as follows:
Distance = 61 km/hr * (time + 20.8/60 s) Distance = 98.5 km/hr * time
We equate the two equations, then we can solve for the time spent on the trip. Hope this answers the question. Have a nice day.
Answer:
no motion means no velocity, so the y values willl always be 0 as ur time (x) value increses
Explanation:
