<h3><u>Answer</u>;</h3>
B. When actin filaments are pulled toward the center of the sarcomere, the fiber shortens.
<h3><u>Explanation;</u></h3>
- <em><u>The events of muscle fiber shortening occurs with in the sacromeres in the fibers. </u></em>
- <em><u>Contraction of striated muscle fibers takes place as the sacromeres shorten as myosin heads pull on the actin filaments.</u></em>
- <em><u>Filament movement starts at the region or zone where thin and thick filaments overlap. </u></em>
- <em><u>Myofibril contains many sacromeres along its length and thuse myofibrils and muscle cells contract as the sacromeres contract.</u></em>
Answer: F=0.075N
Explanation:
T*cos(θ) = mg=0.005X9.8
T*cos(θ)=0.049N
T = 0.049/cosθ
F = k*q1*q2 / r2
F = 8.9875 * 10^9 * q1*q2 / r^2 q1
F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2
F=0.2246875/r^2
r= 2Lsinθ = 2 x 1 x sinθ =2sinθ
Kindly check the attached for further solution
Answer:
The correct answer will be "
".
Explanation:
The time it would take again for current or electricity flows throughout the circuit including its LR modules can be connected its full steady-state condition is equal to approximately 5
as well as five-time constants.
It would be calculated in seconds by:
⇒ 
, where
- R seems to be the resistor function in ohms.
- L seems to be the inductor function in Henries.