That’s a false ?? I’m not that sure , but it’s a maybe .
Answer:
b. actively transport Cl- from the ECF to the external environment.
Explanation:
Chloride cells are cells that are found in the gills of teleost fishes which pump large amount of sodium and chloride ions out from the extracellular fluid (ECF) into the sea or environment against a concentration gradient in marine fish.
The opposite of this process occurs in freshwater fishes where the gills of freshwater teleost fish, cause an influx of sodium and chloride ions into the fish from the environment, also against a concentration gradient.
Mechanism of action
Salt water teleost fishes take in large amounts of seawater to decrease osmotic dehydration. The excess of ions derived from seawater is thrown out of the teleost fishes through the chloride cells. These cells employs active transport on the basolateral (internal) surface to diffuse in chloride, which then is pumped out of the apical (external) surface, straight into the surrounding environment. Such mitochondria-rich cells are located in the region of the gill lamellae and filaments of teleost fish.
The answer would be 25%
Carbon 14 is radioactive material with 5700 year of half-time which will change it into carbon-12, a more stable substance. If the age of the fossil is 11,400 years old, then the amount of half-time passed would be: 11,400 years/ (5,700years/ half-time)= 2 half-time.
Since it undergo 2 half-time, the percentage should be: 100% * (1/2)^2= 25%
Answer:
Comparative embryology is one of the main lines of evidence in support of evolution. In comparative embryology, the anatomy of embryos from different species are compared through the embryos development. Similarities between different species indicate that we all came from a common ancestor.
Explanation:
