All categories

3 years ago

Where does photosynthesis take place?

2 answers:

7 0

In plants, photosynthesis takes place in chloroplasts, which contain the chlorophyll. Chloroplasts are surrounded by a double membrane and contain a third inner membrane, called the thylakoid membrane, that forms long folds within the organelle.

stepan [7]3 years ago

5 0

Answer:

It takes place in the chloroplasts!

Hope this helped out! :)

You might be interested in

What is nitrugen cycle?<br>

stealth61 [152]

Answer:

A repeating process where nitrogen moves through living and non living things like the atmosphere, soil, water, plants, and animals. Nitrogen must change forms in order to go through its cycle.

Explanation:

7 0

3 years ago

A red flowered plant (RR) is crossed with a white flowered plant (WW) and produces plants with pink flowers (RW). If two pink fl

umka2103 [35]

Answer:

It would be 100 % pink.

Explanation:

Pink and Pink make Pink. Just as Red and White make Pink.

6 0

3 years ago

Which of these best describes the concept of the rock cycle

gizmo_the_mogwai [7]

Answer: The rock cycle is a concept of geology that describes the transition of rocks between the three rock types: igneous, sedimentary, and metamorphic. The cycle outlines how each rock type can be converted to another rock type through geologic processes.

Explanation:

7 0

3 years ago

Can someone answer #10 and #11 plzzzz

pogonyaev

I’m so sorry if it’s wrong but I’m going to say that answer for

10.) D.
11.) C.

5 0

4 years ago

In Drosophila, the bar mutant is characterized by eyes that are restricted to a narrow, vertical bar. When a bar female is mated

Lelechka [254]

Answer:

See the answer below

Explanation:

a) The mode of inheritance of the bar mutant is X-linked and dominant.

Assuming that barness is represented by the allele B.

Bar female = $X^BX^B$ or $X^BX^b$

Wild type male = $X^bY$

Bar female x wild type male:

$X^BX^B$ x $X^bY$

$X^BX^b$ $X^BY$ $X^BX^b$ $X^BY$

All of the F1 flies are bar because a single B allele is required for the trait to be expressed.

Bar male x wildtype female

$X^BY$ x $X^bX^b$

$X^BX^b$ $X^BX^b$ $X^bY$ $X^bY$

All the female offspring are barred while all the males are wildtype barred resulting in a 50/50 (857/905 is approximately 50/50) ratio of barred/wildtype offspring.

b) Genotypes of each of the cross above, including the parents and the F1 generations.

1. $X^BX^B$ x $X^bY$

$X^BX^b$ $X^BY$ $X^BX^b$ $X^BY$

2. $X^BY$ x $X^bX^b$

$X^BX^b$ $X^BX^b$ $X^bY$ $X^bY$

4 0

3 years ago