Answer:
waxing crescent: first quarter waning gibbous: third quarter
Explanation:
The moon is waxing (getting larger) in the first quarter after the new moon. It is waning (getting smaller) in the third quarter, after the full moon at the end of the second quarter.
The shape of the moon is a "crescent" when it is less than a semicircle. It is "gibbous" when it is more than a semicircle. As it waxes, the crescent grows until the moon is half-full at the end of the first quarter, then it is a waxing gibbous moon through the second quarter until it is full at the end of the quarter. Following the full moon, it is waning gibbous until it becomes half-full again at the end of the third quarter. Finally, it is a waning crescent through the fourth quarter until the new moon.
waxing crescent: first quarter waning gibbous: third quarter
Judging from it's prevalence and popularity, there will be a long way to go until people start to lose interest with expressing themselves online. So no, social media will not lose its relevance, but maybe when technology is dead, then it will.
Go to settings, personalization, then background. Select the photo file you want to use. Should look like this.
Answer:
The cyber criminals are the people that are engaged with getting the data in an unapproved way and furthermore mischief to the association henceforth are considered as cyber criminals.
Cyber criminals are people or groups of individuals who use innovation to committed the malicious exercises on computerized frameworks or systems with the aim of taking the organization data or individual information and producing benefit.
There are many types of cyber criminals that are:
- Internet stalkers
- Cyber terrorist
- Identity thieves
Answer:
Following are the program in the C++ Programming Language.
//set header file
#include <iostream>
//set namespace
using namespace std;
//define class
class format
{
//set access modifier
public:
//set string type variable
string res;
//define function
void names(string first_name, string last_name)
{
//set if-else if condition to check following conditions
if(first_name.length()>0 && last_name.length()>0)
{
res="Name: "+last_name+", "+first_name;
}
else if(first_name.length()>0 and last_name.length()==0)
{
res="Name: "+first_name;
}
else if(first_name.length()==0 and last_name.length()==0)
{
res="";
}
}
//define function to print result
void out(){
cout<<res<<endl;
}
};
//define main method
int main() {
//set objects of the class
format ob,ob1,ob2;
//call functions through 1st object
ob.names("John","Morris");
ob.out();
//call functions through 2nd object
ob1.names("Jhon","");
ob1.out();
//call functions through 3rd object
ob2.names("", "");
ob2.out();
}
<u>Output</u>:
Name: Morris, John
Name: Jhon
Explanation:
<u>Following are the description of the program</u>:
- Define class "format" and inside the class we define two void data type function.
- Define void data type function "names()" and pass two string data type arguments in its parameter "first_name" and "last_name" then, set the if-else conditional statement to check that if the variable 'first_name' is greater than 0 and 'last_name' is also greater than 0 then, the string "Name" and the following variables added to the variable "res". Then, set else if to check that if the variable 'first_name' is greater than 0 and 'last_name' is equal to 0 then, the string "Name" and the following variable "first_name" added to the variable "res".
- Define void data type function "out()" to print the results of the variable "res".
- Finally, we define main method to pass values and call that functions.
