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Afina-wow [57]
2 years ago
5

What is the answer to x 3,6,9,12 y -6,-12,-18,-24 y=mx+b

Mathematics
1 answer:
Solnce55 [7]2 years ago
4 0

Answer:

The equation of the line or linear function is:

y = -2x

Step-by-step explanation:

Given the table

x        3       6       9        12

y      -6    -12      -18      -24

As there is a constant change in x and y values, so the table represents the linear function.

The slope-intercept form of the linear equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Taking any two points, let say

  • (3, -6)
  • (6, -12)

Determining the slope between (3, -6) and (6, -12)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-12-\left(-6\right)}{6-3}

Refine

m=-2

Thus, the slope m = -2

now substituting m = -2 and (3, -6) in the slope-intercept form

y = mx+b

-6 = -2(3) +b

-6 = -6 + b

b = -6 + 6

b = 0

Thus, the y-intercept b = 0

now substituting m = -2 and b = 0  in the slope-intercept form of linear function

y = mx+b

y = -2x + 0

y = -2x

Therefore, the equation of line or linear function is:

y = -2x

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Order the rational numbers 0.69,13/20,1/2,0.6,17/25 from least to greatest
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A student solves the following equation and
Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}

\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)

\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)

\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)

as

  • \frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)
  • -\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a
  • \frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2

so equation becomes

3\left(a-2\right)-6a=a+2  

-3a-6=a+2

-3a-6+6=a+2+6

-4a=8

\mathrm{Divide\:both\:sides\:by\:}-4

\frac{-4a}{-4}=\frac{8}{-4}

a=-2

\mathrm{Verify\:Solutions}

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}

\mathrm{Solve\:}\:a+2=0:\quad a=-2

\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2

\mathrm{Solve\:}\:a-2=0:\quad a=2

So the following points are undefined

a=-2,\:a=2

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

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