-17 + n/5 = 33
Add 17 to both sides
-17 +n/5 + 17 = 33 + 17
SImplify
n/5 = 50
Multiply 5 to both sides
n/5 * 5 = 50 * 5
n = 250
Option 1: $50
Option 2: $12.50 per hour.
50 ÷ 12.50 = 4
Paul can choose the hourly wage if he works more than 4 hours.
For example, he works 5 hours.
12.50 x 5 hours = 62.50
$62.50 is higher than the fixed rate of $50. Thus, hourly wage is the better option.
Answer:
6.5
Step-by-step explanation:
7 5/8 + 5 3/8= 13
13/2=6.5
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
