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elena-s [515]
2 years ago
15

Hansika paid $9.25 for 2.8 pounds of pretzels. About how much did she pay for a pound of pretzels? ( Round your answer to the ne

arest whole number )
$2.00
$3.00
$4.50
$5.00
Mathematics
2 answers:
Maurinko [17]2 years ago
5 0

Answer:

3.00

Step-by-step explanation:

Rounding down

solniwko [45]2 years ago
4 0

Answer:

$3.00

Step-by-step explanation:

shaminapodiepooo

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If ∠C and ∠D are complementary angles, m∠C = (4x + 3)°, find m∠D = (15x - 8)°, find m∠D.
kykrilka [37]

Answer:

67

Step-by-step explanation:

4x+3+15x-8=90(complementary angle)

x=5

now D = 15*5-8

d=67

8 0
3 years ago
Plz plz help help help plz plz help plz
uranmaximum [27]

Answer:

since your adding to hours each time youll have 11, then the answer would be d the last one :)

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Warren, a golf fan, was curious about how often professional golfers make successful putts from various distances. He looked at
anzhelika [568]

Answer:

Explained below.

Step-by-step explanation:

A correlation coefficient is a mathematical measure of certain kind of correlation, in sense a statistical relationship amid two variables

Negative correlation is a relationship amid two variables in which one variable rises as the other falls, and vice versa.  

Values amid 0.7 and 1.0 (-0.7 and -1.0) implies a strong positive (negative) linear relationship amid the variables.

It is provided that Warren noticed a strong negative linear relationship between the success rate and putt distances.

This implies that as the putt distances are increasing the success rates are decreasing and as the putt distances are decreasing the success rates are increasing.

4 0
3 years ago
Read 2 more answers
1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
molle have 100098765 her mom gave her 800000 A week later she got 90000 Tow dAyS later she spent 900000 how much dose sHe HaVe
dangina [55]

Answer:

100088765

Step-by-step explanation:


7 0
3 years ago
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