If the graph of y=x^2 is vertically stretched by the factor 3, reflected over the x-axis, translated left 7 and up 9, what would
1 answer:
You might be interested in
9514 1404 393
Answer:
240 ft by 480 ft
Step-by-step explanation:
Area is maximized when the long side is half the total length of the fence. That makes the short side (out from the river) be half the length of the long side.
The fenced field dimensions are 240 feet by 480 feet.
__
You can let x represent the length of the long side. Then the length of the short side is half the remaining fence: (960 -x)/2.
The total area is the product of these dimensions:
A = x(960 -x)/2
We note that this is the equation of a parabola with zeros at x=0 and x=960. The maximum will be found on the line of symmetry, halfway between the zeros. That is at x = (0 +960)/2 = 480.
The area is maximized for a long-side dimension of 480 feet. The short sides are 240 feet.
