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lutik1710 [3]
2 years ago
9

What's 2/3 written as a fraction with a denominator of 9? A.2/9 B.3/9 C.6/9 D.9/9

Mathematics
1 answer:
Elza [17]2 years ago
8 0
The answer is C
How many 2s go into 6 and 9
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Find the measure of 41.<br> s<br> 839<br> 41<br> 41 = [?]
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<1=97°

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<1+83=180 co interior angle

<1=180-83=97°

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The price of a 2 dozen gum balls is $4
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The Bluejay Apartments is a new development and is in the process of structuring its lease agreements. The company would like to
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Answer:

The Bluejay Apartments

1. Tax Effects of the following Alternatives:

i. $1,000 damage deposit with no rent prepayment

No tax will be paid by The Bluejay Apartments until the deposit will no longer be refunded.

ii. $500 damage deposit and $500 rent for the final month of the lease

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iii. $1,000 rent for the final two months of the lease and no damage deposit

Tax will be paid on the rent income of $1,000.

b) From a tax point of view, option i is recommended.

Step-by-step explanation:

According to the IRS, a security or damage deposit is not taxable when it is received by the landlord.  It becomes taxable income when the landlord is no longer obligated to return it to the tenant.  The reason a damage deposit is not taxed is that it is recorded as an asset and not an expense or income.

5 0
3 years ago
The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de
antoniya [11.8K]

Answer:

a) P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b) P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c) P(A') = 1-P(A) =1-0.4=0.6

d) P(A \cup B) =0.4 +0.8-0.2 =1.0

e)  The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

Step-by-step explanation:

We have the following space provided:

S= [a,b,c,d,e]

With the following probabilities:

P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

P(A) = 0.1+0.1+0.2 = 0.4

P(B) =0.2+0.4+0.2=0.8

Determine:

a. P(A)

P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b. P(B)

P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c. P(A’)

From definition of complement we have this:

P(A') = 1-P(A) =1-0.4=0.6

d. P(AUB)

Using the total law of probability we got:

P(A \cup B) =P(A) +P(B)-P(A \cap B)

For this case P(A \cap B) = P(c) =0.2, so if we replace we got:

P(A \cup B) =0.4 +0.8-0.2 =1.0

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

8 0
3 years ago
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