Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
kjh7563653 365385 36539y5 53nkddg dhdk djgd ghgkg d99 76 79
Step-by-step explanation:
Answer:
cos-1(-4/14)
Step-by-step explanation:
If
4.5=r
3.5=s
2=t
By law of cosines:

Answer:
x<5
Step-by-step explanation:
2x-3>7 you add three to both sides
2x>10 you then divide 2x by 2 and 10 by 2 which switches the symbol around
x<5 that's the answer
Answer:
See the image below:)
Step-by-step explanation: