What’s the mode(s) of 5,5,4,6,7,4,7,3,4,7,5,3

Divide these polynomial a (27x 4 - 18x 3 + 9x 2) ÷ 3x

Blizzard [7]

The answer is 9x^3-6x^2+3x

5 0

2 years ago

A bag contains 20 pieces of candy. There are 8 grape peices, 7 cherry pieces, and 5 lemon pieces. part a says that one piece is

Alex787 [66]

Grape- 8/20 = 2/5 = 40%
cherry - 7/20 = 35%
lemon - 5/20 = 25%

5 0

3 years ago

Which equation has solution x = -3?

vovangra [49]

If the answer is incorrect , please delete.

Answer is B and D

have a nice days.........

8 0

3 years ago

Pleeeeese help me as fast as you can!!!

Aleonysh [2.5K]

Answer:

A. $y=3x-10$

C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

The given line is $6x+18y=5$

Express this in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept.

$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

$y=3x-10$

On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

8 0

2 years ago

If a cot α = 1 and b cos α = 1, find a2 – b 2

S_A_V [24]

The equivalent expression of the different of two square is -1

Given the following expressions

a cot α = 1

a = 1/cot α = sinα/cosα

b = 1/cos α

We are to find the expression a² - b²

According to difference of two squares;

a² - b² = (a + b) (a - b)

Substitute the given expressions into the formula as shown:

$a^2 - b^2 = (\frac{sin \alpha}{cos \alpha} )^2 - (\frac{1}{cos \alpha} )^2\\a^2 - b^2=\frac{sin^2 \alpha}{cos^2 \alpha} -\frac{1}{cos ^2 \alpha}\\a^2 - b^2=\frac{sin^2 \alpha-1}{cos^2\alpha}\\a^2 - b^2=\frac{-(1-sin^2\alpha)}{cos^2\alpha} \\a^2 - b^2=\frac{-os^2 \alpha}{cos^2 \alpha}\\a^2 - b^2 = -1$

This shows that the equivalent expression of the difference of two squares is -1

Learn more here: brainly.com/question/11084694

4 0

2 years ago