Answer:
2a^2b^3 ^3squareroot4a
Step-by-step explanation:
X is the number
<span>The sum of two numbers is 11, so other number is : 11 - x
</span><span>The sum of their squares is 65
</span>
x^2 + (11 - x)^2 = 65
x^2 + 121 - 2(x)(11) + x^2 = 65
2x^2 - 22x + 121 = 65
2x^2 - 22x + 121 - 65 = 0
2x^2 - 22x + 56 = 0
2(x^2 - 11x + 28) = 0
2(x - 7)(x -4 ) = 0
x - 7 = 0
x = 7
x - 4 =0
x =4
answer: the numbers are 4 and 7
double check:
<span>sum of two numbers is 11:
4 + 7 = 11
</span><span>The sum of their squares is 65
</span><span>4^2 + 17^2 = 16 + 49 = 65
</span>
Answer:
61
Step-by-step explanation:
we kno that a triangle is 180 degrees so we just add the first two angles
37 + 82 = 119
then subtract that from 180
180 - 119 = 61
so x = 61 degrees
lmk if this wrong and ill fix it
hope this helps <3
