Answer:
1
Step-by-step explanation:
using PEDMAS(parentheses, exponents, division, multiply, addition, subtraction) to solve the problem
First we multiply (4)(-3)
(4)(−3)−5−3(−6)
Then multiply -3(-6)
(-12)-5-3(-6)
=-12-5+18
subtract 12-5
-12-5+18
=-17+18
Adding -17+18 gives us 1.
Therefore,  (4)(−3)−5−3(−6) is 1.
 
        
             
        
        
        
Answer:
The answer to your question is below
Step-by-step explanation:
1.- Find the volume of the cylinder
Data
diameter = 9 cm
radius = 4.5 cm
height = 15 cm
Formula 
    V = πr²h
    V = π(4.5)²(15)
    V = 303.75π         This is te answer for the volume in terms of π
        = 952.78 cm³                
2.- Find the volume of the cylinder
height = 40 yd
radius = 12 yd
Formula
    V = πr²h
    V = π(12)²(40)
    V = 5760π              This is te answer for the volume in terms of π
        = 18086.4 cm³
3.- What is the height .......
height = q
side length = r
4.- Volume of a pyramid
     Volume = Area of the base x height
Area of the base = 11 x 11 = 121 cm²
     Volume = 121 x 18
     Volume = 2178 cm³
 
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
The degree of a polynomial is the variable (in this case 1 variable) raised to the highest power. 
Look at the first term: 19x^9
The variable is x
The highest power is 9
So the answer is 9.
 
        
             
        
        
        
Answer:
Every student would have five markers.
Step-by-step explanation:
There would be 20 students, and 100 markers which is 20/100. You would reduce that fraction to 1/5. Therefore, every student would have 5 markers.
 
        
             
        
        
        
We know that there are 100 cm in 1 m. We can convert 0.75 m to cm by multiplying by 100 to give us:

Therefore the path before the addition is 75 cm wide.
Mr. Kassel added 20 cm of blocks on each side of the path, meaning that the added width is actually 40 cm total (20 on each side, and there are 2 sides).
So we need to add 40 cm to the original 75 cm:

So now we have the width of the path in cm, the question asks for the width in meters. We can do this by dividing the width in cm by 100 to get the width in meters:

Now we know that 
the new width of the path is 1.15 m.