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Fantom [35]
2 years ago
6

Find the missing length of the triangle. a= ? b=4 c=12 1/3

Mathematics
1 answer:
Llana [10]2 years ago
3 0

Answer:

a = 12.93

Step-by-step explanation:

Convert to decimal: 12 1/3 = 12.3

Pythagoras (a^2 = b^2 + c^2):

4^2 = 16

12.3^2 = 151.29

16+151.29 = 167.29

a = √167.29

a = 12.93 (rounded to two decimal places)

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Simplify (Are all division)<br><br>2+4i<br>3i<br><br>3+2i<br>4+i<br><br>2i^11
Alla [95]

We\ know:\ i=\sqrt{-1}\to i^2=-1

\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i

\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i

2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i


Used:\ (a+b)(a-b)=a^2-b^2

6 0
3 years ago
Evaluate 150 - ( 2 +x)^ 3 when x - 2
AveGali [126]

Answer:

86

Step-by-step explanation:

(2+2=4) 4 to the 3rd power is 64. 150 minus 64 is 86

3 0
3 years ago
HELP FAST ALL OF MY POINTS TO BE GIVEN TO YOU
gogolik [260]

Answer:

C > 9

Step-by-step explanation:


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3 years ago
EX 6.1 How many iterations will the following for loops execute? for (int i = 0; i &lt; 20; i+ +) { } for (int i = 1; i &lt;= 20
Romashka-Z-Leto [24]

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20, 20, 15, 20, 10, and 5 iterations respectively

Step-by-step explanation:

The loop "for (int i = 0; i < 20; i+ +)" starts at i=0 and increases the counter i by 1 at the end of each iteration. The counter must be less than 20, so the values of i in the loop are 0,1,2,3,...,19. These are 20 values, and thus the code iterated 20 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and increases the counter i by 1 at the end of each iteration. The counter can't exceed 20, so the values of i in the loop are 1,2,3,4,...,20. These are 20 values, and thus the code iterated 20 times.

Similarly, in "for (int i = 5; i < 20; i+ +)" i takes the 15 values are 5,6,7,...,19. Hence, the code iterated 15 times.

The loop "for (int i = 20; i > 0; i- -)" starts at i=20 and decreases the counter i by 1 at the end of each iteration, so the values of i in the loop are 20,19,18,...,1. These are 20 values, then we have 20 iterations.

The loop "for (int i = 1; i < 20; i = i + 2)" starts at i=1 and increases the counter i by 2 at the end of each iteration. The values of i in the loop are 1,3,5,7,...,19. These are 10 values, and thus the code iterated 10 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and multiplies the counter i by 2 at the end of each iteration, so the values of i in the loop are 1,2,4,8,16. Then we have 5 iterations.

6 0
3 years ago
At Southside Middle school, 30% if the students play an instrument. There are 310 students. How many students play an instrument
Svetach [21]
30% converted to a decimal is 0.30
310 x 0.3 = 93 students play an instrument
3 0
3 years ago
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