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Vera_Pavlovna [14]
3 years ago
14

Write an equivalent series with the index of summation beginning at n = 1. ∞ (−1)n + 1(n + 1)xn n = 0

Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Looks like the starting series is

\displaystyle\sum_{n=0}^\infty\left((-1)^n+1\right)(n+1)x^n

Note the degree of the first few terms in the series, for n=0,1,2, are x^0,x^1,x^2, and so on.

So if the series were to start at n=1, we would need to preserve that pattern, and we do that by replacing n with n-1:

\displaystyle\sum_{n=1}^\infty\left((-1)^{n-1}+1\right)(n-1+1)x^{n-1}

Simplifying a bit, we end up with

\displaystyle\sum_{n=1}^\infty\left(1-(-1)^n\right)nx^{n-1}

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Step-by-step explanation:

70-20=50

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1 Selena rewrote the expression 4(5m + 12s) using the distributive property. What expression did Selena create?
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4*5+12

Step-by-step explanation:

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17+36=z-37 what is z
sp2606 [1]

Answer:

The correct answer is 90

Step-by-step explanation:

17 + 36= z- 37   ADD 17 AND 36

53= z-37        BRING 37 OVER TO 53 AND ADD

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2 years ago
The rectangle shown has a perimeter of 48 cm and the given area. Its length is 6 more than twice its width. Write and solve a sy
melamori03 [73]

Answer:

The length of the rectangle is 18 cm

The width of the rectangle is 6 cm

Step-by-step explanation:

Let

x-----> the length of the rectangle

y----> the width of the rectangle

we know that

The perimeter of the rectangle is

P=2(x+y)

we have

P=48\ cm

so

48=2(x+y) ------> equation A

x=2y+6 ------> equation B

Substitute equation B in equation A and solve for y

48=2(2y+6+y)

48=2(3y+6)

48=6y+12

6y=48-12

y=36/6=6 cm

Find the value of x

x=2(6)+6=18 cm

The area of the rectangle is

A=xy

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4 0
3 years ago
Which statements are always true regarding the diagram? Check all that apply. m∠3 + m∠4 = 180° m∠2 + m∠4 + m∠6 = 180° m∠2 + m∠4
Nostrana [21]

Answer:

The true statements are:

m∠ 3 + m∠ 4 = 180° ⇒ 1st

m∠ 2 + m∠ 4 + m∠ 6 = 180° ⇒ 2nd

m∠ 2 + m∠ 4 = m∠ 5 ⇒ 3rd

Step-by-step explanation:

* Look to the attached diagram to answer the question

# m∠ 3 + m∠ 4 = 180°

∵ ∠ 3 and ∠ 4 formed a straight angle

∵ The measure of the straight angle is 180°

∴ m∠ 3 + m∠ 4 = 180° ⇒ <em>true</em>

# m∠ 2 + m∠ 4 + m∠ 6 = 180°

∵ ∠ 2 , ∠ 4 , ∠ 6 are the interior angles of the triangle

∵ The sum of the measures of interior angles of any Δ is 180°

∴ m∠ 2 + m∠ 4 + m∠ 6 = 180° ⇒ <em>true</em>

# m∠ 2 + m∠ 4 = m∠ 5

∵ In any Δ, the measure of the exterior angle at one vertex of the

  triangle equals the sum of the measures of the opposite interior

  angles of this vertex

∵ ∠ 5 is the exterior angle of the vertex of ∠ 6

∵ ∠2 and ∠ 4 are the opposite interior angles to ∠ 6

∴ m∠ 2 + m∠ 4 = m∠ 5 ⇒ <em>true </em>

# m∠1 + m∠2 = 90°

∵ ∠ 1 and ∠ 2 formed a straight angle

∵ The measure of the straight angle is 180°

∴ m∠1 + m∠2 = 90° ⇒ <em>Not true</em>

# m∠4 + m∠6 = m∠2

∵ ∠ 4 , ∠ 6 , ∠ 2 are the interior angles of a triangle

∵ There is no given about their measures

∴ We can not says that the sum of the measures of ∠ 4 and ∠ 6 is

  equal to the measure of ∠ 2

∴ m∠4 + m∠6 = m∠2 ⇒ <em>Not true</em>

<em></em>

# m∠2 + m∠6 = m∠5

∵ ∠ 5 is the exterior angle at the vertex of ∠ 6

∴ m∠ 2 + m∠ 6 = m∠ 5 ⇒ <em>Not true</em>

6 0
3 years ago
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