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Vera_Pavlovna [14]
3 years ago
14

Write an equivalent series with the index of summation beginning at n = 1. ∞ (−1)n + 1(n + 1)xn n = 0

Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Looks like the starting series is

\displaystyle\sum_{n=0}^\infty\left((-1)^n+1\right)(n+1)x^n

Note the degree of the first few terms in the series, for n=0,1,2, are x^0,x^1,x^2, and so on.

So if the series were to start at n=1, we would need to preserve that pattern, and we do that by replacing n with n-1:

\displaystyle\sum_{n=1}^\infty\left((-1)^{n-1}+1\right)(n-1+1)x^{n-1}

Simplifying a bit, we end up with

\displaystyle\sum_{n=1}^\infty\left(1-(-1)^n\right)nx^{n-1}

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