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3 years ago

Is the equation x9 – 5x3 + 6 = 0 quadratic in form? Explain why or why not.

2 answers:

6 0

NoThe equation is not quadratic in form.The variable part of the first term is not the square of the variable part of the
second term.The result of squaring x cubed is x to the 6thpower, not the 9th power.x9 (x3)2

hichkok12 [17]3 years ago

5 0

The given equation, x9 - 5x3 + 6 = 0, is not a quadratic equation because the exponent of the first term is 9 while that of the second term is 3. The square of 3. If we are to square x3, we should only be getting x6 instead of x9. Therefore, the answer is NO.

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What is the product of the rational expressions below

ankoles [38]

The answer to the question is a

8 0

3 years ago

A 15 pound bag of candy cost $9.99. How much does 1 pound of candy cost? How do you know? Make sure to show all work and answer

Law Incorporation [45]

All you would do is divide 9.99/15 to get how much one pound costs.

The answer would be around 66 or 67 cents.

9.99/15=.666

5 0

3 years ago

Read 2 more answers

Find the critical value t a/2 needed to construct a confidence interval of the given level with the given sample size. level 95%

stepan [7]

Α = 1- (95/100) = 1-0.95 = 0.05

p = 1- α/2 = 1- 0.05/2 = 1-0.025 = 0.975

Degrees of freedom, df = Sample size -1 = 11-1 = 10

From t-tables, with cumulative probability pf 0.975 and df of 10,
Critical value = 2.228

7 0

3 years ago

Solve these compound interest problems and round your answer to the nearest 100th.

MatroZZZ [7]

Answer:

$2,226.96

Step-by-step explanation:

You are going to want to use the compound interest formula, which is shown below.

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate

n = number of times compounded annually

t = time

First, change 10% into its decimal form:

10% -> $\frac{10}{100}$ -> 0.1

Now lets plug in the values into the equation:

$A=500(1+\frac{0.1}{12})^{15(12)}$

$A=2,226.96$

The final amount after 15 years is $2,226.96

4 0

3 years ago

. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an

Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12$