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GuDViN [60]
3 years ago
9

Is the equation x9 – 5x3 + 6 = 0 quadratic in form? Explain why or why not.

Mathematics
2 answers:
Lapatulllka [165]3 years ago
6 0
NoThe equation is not quadratic in form.<span>The variable part of the first term is not the square of the variable part of the
second term.</span><span>The result of squaring x cubed is x to the 6thpower, not the 9th power.</span><span>x9 (x3)<span>2</span></span>
hichkok12 [17]3 years ago
5 0
The given equation, x9 - 5x3 + 6 = 0, is not a quadratic equation because the exponent of the first term is 9 while that of the second term is 3. The square of 3. If we are to square x3, we should only be getting x6 instead of x9. Therefore, the answer is NO. 
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Answer:

B.

Step-by-step explanation:

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In a forested area, the number of trees, T can be expressed as a function of the initial number of trees planted. If the initial
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N = N    (1+0.20)^5    
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Avni designs a game in which a player either wins or loses 4 points during each turn. Which equation represents all numbers of p
Ierofanga [76]

Answer:

C |p| = 4

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If a player wins 4points during each turn, then, the total points will be +4points

If the player looses 4points, total points lost will be -4points

The total number of point p the player can have will be represented as;

|p| = 4 (since is both positive and negative 4 )

Note that the nodulus of a variable will return both positive and negative value of that variable

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3 years ago
Jack invested some money in a bank at a fixed rate of interest compounded annually. The equation below shows the value of his in
schepotkina [342]

Answer: The average rate of change of Jack's investment from the third year to the fifth year is $6.43

Step-by-step explanation:

The function that defines the value of his investment after x years,

Putting the value of x as 3 and 5, we can get the value of his investment after 3 years and 5 years respectively.

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3 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
3 years ago
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