NoThe equation is not quadratic in form.<span>The variable part of the first term is not the square of the variable part of the second term.</span><span>The result of squaring x cubed is x to the 6thpower, not the 9th power.</span><span>x9 (x3)<span>2</span></span>
The given equation, x9 - 5x3 + 6 = 0, is not a quadratic equation because the exponent of the first term is 9 while that of the second term is 3. The square of 3. If we are to square x3, we should only be getting x6 instead of x9. Therefore, the answer is NO.
