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BigorU [14]
3 years ago
6

Twenty-seven is 25% of

Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0

Let's firs rewrite this problem to say 27 is 25% of what number.

Reading through the problem we have <em>27 is</em>, that's <em>27 equals</em>,

<em>25%</em>, <em>25/100</em>, <em>of</em>, <em>times</em>, <em>what number</em>, <em>x</em>.

Notice about that I put 25% as the fraction 25/100. This is because <u><em>percent</em></u> means <em>over 100</em> so 25% means 25 over 100 or 25/100.

So now, our equation reads 27 = 25/100 · X.

Reducing the 25/100 to 1/4, we have 27 = 1x/4.

Multiplying both sides by 4 to get rid of the fraction, we have 108 = 1x.

Divide both sides by 1 to isolate <em>x</em> and we find that 108 = x.

So, 27 is 25% of 108.

DENIUS [597]3 years ago
5 0

Well...

27 = 25% (1/4) × a

27 = 1/4a

a = 27 x 4 = 108

answer: 108

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WHAT IS THE QUESTION ON KENDRA'S HOMEWORK?
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3 years ago
I FORGOT THE LAST ONE
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I think it’s 3.2 but I don’t know
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Ms. Fontanges wants to put a line of bricks along the back edge of her yard. She needs 35 feet of bricks. The bricks she wants t
Oliga [24]

Answer:

$41.16

Step-by-step explanation:

Length of bricks required = 35 feet, length of brick sold = 10 inches, cost of 10 inches brick = $0.98 per brick

Total number of brick required to build the back yard = Length of bricks required ÷ Length of brick sold

1 ft = 12 inches

Number of brick required = (35 * 12) ÷ 10

Number of bricks required = 42 bricks

Cost of brick required = Per length cost of brick * Number of bricks required

Cost of brick required = 0.98 * 42

Cost of brick required = $41.16

Ms. Fontanges would spend $41.16 on the purchase of bricks

5 0
3 years ago
Using the equation y = 2x + 5 , what would the input need to be for an output of -45?
Semenov [28]

Answer:

-25

Step-by-step explanation:

Essentially, y is your output and x is your input.

Here's your base equation: y = 2x + 5

Knowing the information above, let's plug it in:

-45 = 2x + 5

(Subtract 5 from both sides)

-50 = 2x

(Divide both sides by 2 to isolate x)

-25 = x

And there you go.

3 0
3 years ago
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¿De cuántas formas podemos cambiar un billete de 5000 por monedas de 500 y de 200,si tenemos q utilizar al menos de cada denomin
NARA [144]

Answer:

Existen 6 formas posibles de cambiar un billete de 5000 por monedas de 200 y 500.

Step-by-step explanation:

En primer lugar, se determina el mínimo común múltiplo de 500 y 200. Si se multiplica a 500 por 2 y a 200 por 5, se encuentra que el mínimo común múltiplo es 1000. Entonces, se encuentra las siguientes dos conclusiones:

1) Se requiere dos monedas de 500 para obtener 1000.

2) Se requiere cinco monedas de 200 para obtener 1000.

Para determinar todas las formas posibles sin considerar el orden de las monedas, se requiere estudiar tres escenarios:

(i) Todas las monedas son de 200.

(ii) Todas las monedas son de 500.

(iii) Hay monedas de 200 y 500.

Caso 1 - Todas las monedas son de 200:

Es evidente que solo existe una forma.

Caso 2 - Todas las monedas son de 500:

Es evidente que solo existe una forma.

Caso 3 - Hay monedas de 200 y 500:

Existen las siguientes formas:

- 1000 en monedas de 200, 4000 en monedas de 500.

- 2000 en monedas de 200, 3000 en monedas de 500.

- 3000 en monedas de 200, 2000 en monedas de 500.

- 4000 en monedas de 200, 1000 en monedas de 500.

En resumen, existen 4 escenarios.

Finalmente, existen 6 formas posibles de cambiar un billete de 5000 por monedas de 200 y 500.

4 0
3 years ago
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