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BigorU [14]
3 years ago
6

Twenty-seven is 25% of

Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0

Let's firs rewrite this problem to say 27 is 25% of what number.

Reading through the problem we have <em>27 is</em>, that's <em>27 equals</em>,

<em>25%</em>, <em>25/100</em>, <em>of</em>, <em>times</em>, <em>what number</em>, <em>x</em>.

Notice about that I put 25% as the fraction 25/100. This is because <u><em>percent</em></u> means <em>over 100</em> so 25% means 25 over 100 or 25/100.

So now, our equation reads 27 = 25/100 · X.

Reducing the 25/100 to 1/4, we have 27 = 1x/4.

Multiplying both sides by 4 to get rid of the fraction, we have 108 = 1x.

Divide both sides by 1 to isolate <em>x</em> and we find that 108 = x.

So, 27 is 25% of 108.

DENIUS [597]3 years ago
5 0

Well...

27 = 25% (1/4) × a

27 = 1/4a

a = 27 x 4 = 108

answer: 108

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The differencee of 3 times a number and 18 is 39
Bingel [31]

Answer:

3x-18 = 39

3x = 57

x = 19

(3*(19))-18 = 39

57-18 = 39  

3x-x+2=4

Step-by-step explanation:

hope it help

7 0
3 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
2 years ago
What is the answers to <br>8x-2-5x+7= ​
Ludmilka [50]

Answer: 3x +5

Step-by-step explanation:

Group the variables first 8x-5x is 3x. Then look at the numbers -2+7 is 5.

You can't combine letters and numbers so it's as far as you can go.

3 0
3 years ago
Kenneth earns $450 for working 37 1/2 hours. If Kenneth works for 42 hours next week, how much will he earn. A.255.00. B.12.00.
iren2701 [21]

Answer:

Kenneth will earn about $ 504 the next week

Step-by-step explanation:

The first thing we will have to figure out is how much Kenneth earns per hour. Then we can get how much he will earn when he wors for 42 hours.

to get Kenneth's wage per hour, we will divide the sum he is paid in the first week by the number of hours he worked that week.

This is 450/ 37.5 = 12 dollars per hour.

Kenneth earns $12 per hour.

If Kenneth works for 42 hours, he will earn 42 X 12 = $ 504 the next week

5 0
2 years ago
A club consisting of 6 juniors and 8 seniors is to be formed from a group of 13 juniors and 16 seniors. How many different clubs
Vilka [71]

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

C = \frac{N!}{(N-K)!*K!}

For the juniors we have N = 13 and K = 6

Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716

For the seniors we have N = 16 and K = 8

Cs = \frac{16!}{8!8!}  = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

5 0
3 years ago
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