A sphere has a volume of 36tt in3 find the radius of the sphere
2 answers:
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Answer:
BD = <u>1</u> unit
AD = <u>1</u> unit
AB = <u>1.6</u> units
AC = <u>1.6</u> units
Step-by-step explanation:
In the picture attached, the triangle ABC is shown.
Given that triangle ABC is isosceles, then ∠B = ∠C
∠A + ∠B + ∠C = 180°
36° + 2∠B = 180°
∠B = (180° - 36°)/2
∠B = ∠C = 72°
From Law of Sines:
sin(∠A)/BC = sin(∠B)/AC = sin(∠C)/AB
(Remember that BC is 1 unit long)
AB = AC = sin(72°)/sin(36°) = 1.6
In triangle ABD, ∠B = 72°/2 = 36°, then:
∠A + ∠B + ∠D = 180°
36° + 36° + ∠D = 180°
∠D = 180° - 36° - 36° = 108°
From Law of Sines:
sin(∠A)/BD = sin(∠B)/AD = sin(∠D)/AB
(now ∠A = ∠B)
BD = AD = sin(∠A)*AB/sin(∠D)
BD = AD = sin(36°)*1.6/sin(108°) = 1
Answer:
The value of the test statistic is
Step-by-step explanation:
The formula for the test statistic is:
In which X is the statistic, is the mean,
is the standard deviation and n is the number of observations.
In this problem, we have that:
So
The value of the test statistic is
Answer:
R(-3, 8)
Step-by-step explanation:
R = 2Q -P
R = 2(4, 3) -(11, -2) = (8-11, 6+2)
R = (-3, 8)
_____
You can derive the formula for the endpoint from the formula for the midpoint:
Q = (R + P)/2
R = 2Q - P . . . . . . multiply by 2 and subtract P
