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4 years ago

I need help on how to solve this!

Mathematics

2 answers:

sweet [91]4 years ago

7 0

I hope this helps you

2. (b-4)= 6.b

2b-8=6b

8b= -8

b= -1

lesya692 [45]4 years ago

7 0

2(b-4)=6b
2b - 8 = 6b
-8 = 6b - 2b
-8 = 4b
b= -2

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Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

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Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

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