7 men have 7 wives.
2 answers:
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The given sequence is
Write the first 4 terms.
When n=1, obtain
a₁ = 2
When n=2, obtain
a₂ = -4a₁ + 2
= -4(2) + 2 = -8 + 2
= -6
When n=3, obtain
a₃ = -4a₂ + 2
= -4(-6) + 2 = 24 + 2
= 26
When n=4, obtain
a₄ = -4a₃ + 2
= -4(26) + 2 = -104 + 2
= -102
Answer: a₄ = -102
Write the first 4 terms.
When n=1, obtain
a₁ = 2
When n=2, obtain
a₂ = -4a₁ + 2
= -4(2) + 2 = -8 + 2
= -6
When n=3, obtain
a₃ = -4a₂ + 2
= -4(-6) + 2 = 24 + 2
= 26
When n=4, obtain
a₄ = -4a₃ + 2
= -4(26) + 2 = -104 + 2
= -102
Answer: a₄ = -102
Answer:
56.5 ft
Step-by-step explanation:
Here we know that:
- Keisha swims 18 feet from one side of her circular pool to the other swimming straight through the center --> this means that the diameter of the swimming pool is 18 feet, so
d = 18 ft
- Then, she swims one time around the entire edge of her swimming pool. --> this means that she swims along the perimeter of the swimming pool
The perimeter of a circle is given by
where d is the diameter. Therefore in this case, the length of Keisha's second swim is: