How can I describe an angle's measure. PLEASE HELP ASAP

1 answer:

7 0

<span>I answered your question.</span>

Place the midpoint of the protractor on the VERTEX of the angle.Line up one side of the angle with the zero line of the protractor (where you see the number 0).Read the degrees where the other side crosses the number scale.

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Given f(x) = 2x and g(x) = x^2 + 3, find f(g(x))

levacccp [35]

Answer:

2x² + 6

Step-by-step explanation:

f(g(x)) = 2(g(x))

= 2(x² + 3)

= 2x² + 6

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4 years ago

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S_A_V [24]

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iogann1982 [59]

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4 0

3 years ago

Read 2 more answers

How do you solve this?

rewona [7]

$\text{L.H.S}\\\\=\begin{vmatrix} 1 & bc& b+c\\ 1 & ca& c+a\\ 1 &ab&a+b\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & bc& b+c-(a+b+c)\\ 1 & ca& c+a-(a+b+c)\\ 1 &ab&a+b-(a+b+c)\end{vmatrix}~~~~~~~~~~~~~~~;c_3\rightarrow c_3 -(a+b+c)c_1\\\\\\=\begin{vmatrix} 1 & bc& -a\\ 1 & ca& -b\\ 1 &ab&-c\end{vmatrix}\\\\\\=\dfrac 1{abc}\begin{vmatrix} a & abc& -a^2\\ b & abc& -b^2\\ c &abc&-c^2\end{vmatrix}\\\\\\=-\dfrac {abc}{abc}\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\$

$=-1\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\\\\\=-1 \times -1 \begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\text{R.H.S}\\\\\text{Showed.}$

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2 years ago

Solve -10v+2/5z+6=-2 for z.

Kryger [21]

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