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laiz [17]
3 years ago
7

Select the correct answer.

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

C

Step-by-step explanation:

since -6 and -6 are factors of 36 that add up to equal -12, the factored form of the expression is (x-6)^2.

You might be interested in
For what value(s) of k will the relation not be a function?
kolbaska11 [484]

Answer:

  • See below

Step-by-step explanation:

The relation is not a function when x -value is same but y- values are different.

#1

  • k^2 = 4k
  • k = 0, k = 4

#2

  • k^2 - 5k = k + 7
  • k^2 - 6k = 7
  • k^2 - 6k + 9 = 16
  • k - 3 = 4 ⇒ k = 7
  • k - 3 = -4 ⇒ k = -1

#3

  • k^3 - 5k^2 + 3k = -k
  • k^3 - 5k^2 + 4k = 0
  • k(k^2 - 5k + 4) = 0
  • k = 0, k = 1, k = 4

#4

  • |k + 1| + 2 = 8
  • |k + 1| = 6
  • k = 5, k = -7
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bw%7D%7B%20-6%7D%20%20%3D%206" id="TexFormula1" title=" \frac{w}{ -6} = 6" alt="
AfilCa [17]
Answer : w = (-36)
By transposition method -6 when transposed to the other side it becomes multiplication which will be w = 6*(-6)
= w = (-36)
3 0
3 years ago
Read 2 more answers
Pls help. I am not very smart!
Yanka [14]

Answer:

Umm I'm not entirely sure but I think its the last one

8 0
3 years ago
Read 2 more answers
I WILL GIVE U BRAINLY!!
KiRa [710]

Answer:

prime i think sooooooooooooo

6 0
3 years ago
In 1998, Cathy's age is equal to the sum of the four digits in the year of her birthday, then how old was Cathy in 1998?
ycow [4]

Answer:

<em>Cathy was born in 1980 and she was 18 years old in 1998</em>

Step-by-step explanation:

<u>Equations</u>

This is a special type of equations where all the unknowns must be integers and limited to a range [0,9] because they are the digits of a number.

Let's say Cathy was born in the year x formed by the ordered digits abcd. A number expressed by its digits can be calculated as

x=1000a+100b+10c+d

In 1998, Cathy's age was

1998-(1000a+100b+10c+d)

And it must be equal to the sum of the four digits

1998-(1000a+100b+10c+d)=a+b+c+d

Rearranging

1998=1001a+101b+11c+2d

We are sure a=1, b=9 because Cathy's age is limited to having been born in the same century and millennium. Thus

1998=1001+909+11c+2d

Operating

88=11c+2d

If now we try some values for c we notice there is only one possible valid combination, since c and d must be integers in the range [0,9]

c=8, d=0

Thus, Cathy was born in 1980 and she was 18 years old in 1998. Note that 1+9+8+0=18

5 0
3 years ago
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