Consider the charge for parking one car for t hours.
If t is more than 1, then the function is y=3+2(t-1), because 3 $ are payed for the first hour, then for t-1 of the left hours, we pay 2 $.
If t is one, then the rule y=3+2(t-1) still calculates the charge of 3 $, because substituting t with one in the formula yields 3.
75% is 75/100 or 0.75.
For whatever number of hours t, the charge for the first car is 3+2(t-1) $, and whatever that expression is, the price for the second car and third car will be
0.75 times 3+2(t-1). Thus, the charge for the 3 cars is given by:
3+2(t-1)+0.75[3+2(t-1)]+0.75[3+2(t-1)]=3+2(t-1)+<span>0.75 × 2[3 + 2(t − 1)].
Thus, the function which total parking charge of parking 3 cars for t hours is:
</span><span>f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1))
Answer: C</span>
Of each ones place.... Or ... The sum of each number? Just trying to help.....
Any value of y, except when y = -4.9, will make the expression equal to 2.45.
Answer:
Step-by-step explanation:
1) Reagrupar términos.
3(5x + 1) = 15x^3
2) Divide ambos lados por tres.
5x + 1 = 5x^3
3) Mueva todos los términos a un lado.
5x + 1 - 5x^3 = 0
4) No se encontró ninguna raíz algebraicamente. Sin embargo, las siguientes raíces se encontraron por métodos numéricos.
x=−0.878886,−0.209148,1.088033
