I NEED HELP PLEASE VERY QUICKLY WITH WORK SHOWN

If aa skateboard ramp is 15 meters long and it extends 12 meters from the base of the starting point. How high is the ramp?

guapka [62]

The height of the ramp is 9 meter

Solution:

It is given that a skateboard ramp is 15 meters long and it extends 12 meters from the base of the starting point.

If we look at the sum, closely we understand that the ramp is a right angled triangle.

Which has a base length of 12 metres and a hypotenuse of 15 metres.

We need to find its height.

To do so we can use the Pythagoras theorem

Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

By above definition, we get

$\text {Hypotenuse}^{2}=\text {height}^{2}+\text { base }^{2}$

Since we already know the lengths of the hypotenuse and base we can substitute them in the formula and solve for the height.

Let height of the ramp be denoted by ‘h’

$\begin{array}{l}{15^{2}=12^{2}+h^{2}} \\\\ {225=144+h^{2}} \\\\ {225-144=h^{2}} \\\\ {81=h^{2}} \\\\ {h=\sqrt{81}} \\\\ {h=9}\end{array}$

Therefore, the height of the ramp is 9 meter

3 0

3 years ago

the surface area of a cuboid is 95cm² and its lateral surface area is 63cm². find the area of its base

wel

Answer:

The Area of the base is 16 cm² .

Step-by-step explanation:

Given as :

The surface area of the cuboid = x = 95 cm²

The lateral surface area of the cuboid = y = 63 cm²

Let The Area of the base = z cm²

Now, Let The length of cuboid = l cm

The breadth of cuboid = b cm

The height of cuboid = h cm

According to question

∵ The surface area of the cuboid = 2 ×(length × breadth + breadth × height + height × length)

Or, x = 2 ×(l × b + b × h + h × l)

Or, 95 = 2 ×(l × b + b × h + h × l)

Or, (l × b + b × h + h × l) = $\dfrac{95}{2}$ ....1

Similarly

∵lateral surface area of the cuboid = 2 ×(breadth × height + length × height)

Or, y = 2 ×(b × h + l × h)

Or, 2 ×(b × h + l × h) = 63

Or, (b × h + l × h) = $\dfrac{63}{2}$ ......2

Putting value of eq 2 into eq 1

so, (l × b + $\dfrac{63}{2}$ ) = $\dfrac{95}{2}$

Or, l × b = $\dfrac{95}{2}$ - $\dfrac{63}{2}$

Or, l × b = $\dfrac{95 - 63}{2}$

i.e l × b = $\dfrac{32}{2}$

so, l × b = 16

Now, Again

∵The Area of the base = ( length × breadth ) cm²

So, z = l × b

i.e z = 16 cm²

So, The Area of the base = z = 16 cm²

Hence,The Area of the base is 16 cm² . Answer

5 0

3 years ago

Hi can some1 help quickly :) tysm

frez [133]

Answer:

1:2 is the simplest form

Step-by-step explanation:

the ratio is 4:2 but since That's not the simplest form, you must find the GCF. the GCF is 2, divide both numbers by 2 and you get 2:1. you pull the ratio from segment AB and segment DF since both of them have measurements already stated.

hope this helps! :)

8 0

2 years ago

Is 262 a natural number?

MatroZZZ [7]

Yes it is a natural number

3 0

3 years ago

Read 2 more answers

X=-4+y and -2x-5y=15

Scrat [10]

Answer:

x=-5, y=-1

Step-by-step explanation:

Substitute x=-4+y into -2x-5y=15. So we have

-2(-4+y)-5y=15

8-2y-5y=15

-7y=7

y=-1

And x is -4+y so x= -4+(-1)= -5.

7 0

3 years ago