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2 years ago

Write in Standard Form: 9a^2 + 5 = 0

Mathematics

1 answer:

Levart [38]2 years ago

4 0

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

It is in standard form!!!

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

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Help me please this test is very important !

Lilit [14]

Answer:

Step-by-step explanation:

5>2n+11

5-11>2n

-6>2n

-6/2>n

n<or equal to -3

bubble is filled pointing left

6 0

2 years ago

Use co.patible numbers to find two estimates 73÷4,858

Svet_ta [14]

NO.2 answer is 5088.052869

6 0

3 years ago

Write an expression that is equivalent to 2/3(4x + 9). (4 points) Select one: a. 8/3x + 6 b. 8/3x + 9 c. 2/3x + 6 d. 2/3x + 9

Lady_Fox [76]

You have to distribute the 2/3 across the equation.

8/3x+18/3 which is 8/3x+6 so the answer is a

I hope that helps

3 0

2 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

2 years ago

The mass of Jupiter is 1.898 × 10(27) kilograms, and the mass of Saturn is 5.68 × 10(26) kilograms. How much greater is Jupiter'

grandymaker [24]

Just subtract but take care of the power or else you can come up with wrong results !

so first make the power same ;

for Jupiter = 1.898× 10(27) = 18.98 × 10(26)
for Saturn = 5.68×10(26)

so now subtract = (18.98-5.68) × 10(26)
= 13.3 × 10(26)

so the answer is 13.3 ×10(26)
or, 1.33× 10(27)

6 0

2 years ago