Which statement identifies the effect of replacing h(x) with h(-x) on the graph?

The height of a triangle is half the length of its base. The area of the triangle is 12.25cm. Find the height

pentagon [3]

Answer: The height of the triangle is: " 3.5 cm " .
_______________________________________________________

Note: The formula/equation for the area, "A" , of a triangle is:

A = (1/2) * b * h ; or write as: A = (b * h) / 2 ;
_________________________________________________
in which: "A = area of the triangle" ;
"b = base length" ;
"h = "[perpendicular] height" ;
_________________________________________________
Given: h = (b/2) ;
A = 12.25 cm²
{Note: Let us assume that the given area was "12.25 cm² " .}.
_________________________________________________
We are to find the height, "h" ;

The formula for the Area, "A", is: A = (b * h) / 2 ;

Let us rearrange the formula ;
to isolate the "h" (height) on one side of the equation;

→ Multiply EACH side of the equation by "2" ; to eliminate the "fraction" ;

2*A = [ (b * h) / 2 ] * 2 ;

to get: " 2A = b * h " ;

↔ " b * h = 2A " ;

Divide EACH SIDE of the equation by "b" ; to isolate "h" on one side of the equation:

 → (b * h) / b = (2A) / b ;

to get:

 → h = 2A / b ;

Since "h = b/2" ; subtitute "b/2" for "h" ;

Plug in: "12.25 cm² " for "A" ;

→ b/2 = 2A/b ; → Note: " 2A/b = [2* (12.25 cm²) ] / b " ;

Note: " 2* (12.25 cm²) = 24.5 cm² ;

Rewrite as:

→ b/2 = (24.5 cm²) / b ;
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Cross-multiply: b*b = (24.5 cm²) *2 ;

to get: b² = 49 cm² ;

Take the "positive square root" of each side of the equation" ;
to isolate "b" on one side of the equation ; & to solve for "b" ;

→ +√(b²) = +√(49 cm²) ;

→ b = 7 cm ;

Now, we want to solve for "h" (the height) :
_________________________________________________________
→ h = b / 2 = 7 cm / 2 = 3.5 cm ;
_________________________________________________________
Answer: The height of the triangle is: " 3.5 cm " .
_________________________________________________________

6 0

3 years ago

A sink contains 16 liters of water before the drain is opened. It drains at a rate of 2 liters per minute.

AysviL [449]

Answer:

8

Step-by-step explanation:

16 liters divided by 2 liters a minute you get 8

also i would do a graph but there is no way of putting it up with my answer i hope this helps a little if it doesnt im sorry

6 0

3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

so

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago

Which of The following system of equations is solved, what would be the value of the Y coordinate?

Marat540 [252]

The answer would be D) -2

6 0

3 years ago

Read 2 more answers

26/100 in simple form

shepuryov [24]

Is .26 as it shows in the picture I hope this helps

8 0

4 years ago