Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Answer:
B.
Step-by-step explanation:
When the number is positive and not inside the parentheses it means it gets translated up.
For this case we must find the unit cost (dollars per pound) of each site and then compare.
We take into account that:
1kg equals 2.205 pounds
So, we have:
Site 1:
Site 2:
So, the unit cost is:
Thus, the best deal is on site 2.
ANswer:
The best deal is on site 2.
Answer:
-2 ≤ n < 8
Step-by-step explanation:
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