You question isn't clear, but I assume that you are asking for the slop of a line parallel to y=-(5/4)(x)+7.
The line parallel would have a slop of -5/7 and the line perpendicular would have a slop of 5/7.
The difference between the two answers is the sign of the two slopes, one is positive the other is negative
t=100
p=3000
t 1/2 = 20
Try inserting the numbers in the half-life formula.
Answer:
y=6/5x-8
Step-by-step explanation:
Hi there!
We want to find the equation of the line that passes through (5, -2) and has the slope of 6/5
We can write the equation of the line in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept.
Since we are already given the slope of the line, we can immediately plug it into the equation:
y=6/5x+b
Now we need to find b
Since the equation passes through the point (5, -2), we can use it to solve for b
Substitute 5 as x and -2 as y:
-2=6/5(5)+b
Multiply
-2=6+b
Subtract 6 from both sides
-8=b
Substitute -8 as b.
y=6/5x-8
Hope this helps!
Answer:
g(-2) = -15, g(0) = -9, g(3) = -18
Step-by-step explanation:
g(-2) = -2*2 + 3(-2) - 5 g(-2) = -4 - 6 - 5g(-2) = -15g(0) = -4 - 0 - 5g(0) = -9g(3) = -4 - 3(3) - 5g(3) = -4 - 9 - 5g(3) = -18
I HOPE THIS HELPS
Answer:
y = 0.20m + 10, 100 minutes
Step-by-step explanation:
Equation: y = mx + b
Fill it in.
m = slope = 0.20
b = y-intercept = 10
y = 0.20x + 10 (They wanted the variable to be m. So, changing that.)
y = 0.20m + 10
Fill in.
30 = 0.20m + 10
Solve.
20 = 0.20m
100 = m
She was on the phone for 100 minutes.
