To find the area of the larger figure, let's multiply the length by the width.
9 ft * 4 ft = 36ft^2
Let's do the same thing with the smaller figure.
3 ft * 4 ft = 12ft^2
Let's add the area of both figures together.
36ft^2 + 12ft^2 = 48ft^2
We breakdown the components of the distances.
(1) 90 miles west.
x - component = -90 miles
y - component = 0 miles
(2) 80 miles, northwest (120°)
x - component = (80 miles)*(sin 30°) = 40 miles (negative)
y - component =(80 miles)*(cos 30°) = 69.282 miles (positive)
Solve for the distance,
√(-90 - - 40)² + (69.282 miles)² = <em>147.31 miles</em>
The answer would be twenty: 20
Two inequalities:
x > 5 (should be greater than 5 feet)
x < 30 (should be smaller than 30 feet)
One compound inequality: (more convenient inequality)
5 < x < 30
