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bonufazy [111]
3 years ago
11

"Find the midpoint of AB .

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

The midpoint of AB = (x,y)=(1,1)

Step-by-step explanation:

Given : A line AB

To find : Midpoint of AB.

Solution :

Consider the figure


Then , Points of A =    (x_{1} ,y_{1} )   = (-2,0)


Points of B =    (x_{2} ,y_{2} )   = (4,2)


Now to find mid point we will use midpoint formula :


(x,y) =(\frac{x_{1} +x_{2} }{2},\frac{y_{1} +y_{2} }{2} )


(x,y) =(\frac{-2 +4 }{2},\frac{0 +2 }{2} )


(x,y) =(\frac{2 }{2},\frac{2 }{2} )


(x,y) =(1,1 )


Thus, The midpoint of AB = (x,y)=(1,1)






snow_tiger [21]3 years ago
3 0
Hola amigo! :3

The answer would be (1,1)
So B is correct.
Hope this helps.

Adios amigo. 
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erma4kov [3.2K]

The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

y = ax^2 + bx + c

The given quadratic equation is 24x^2 + 2x = 15

Let's rearrange the equation

24x^2 + 2x = 15\\24x^2 + 2x - 15 = 0

This implies that

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  • c = -15

The equation or formula of quadratic formula is given as

y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}

We can substitute the values into the equation and solve

y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}

From the calculations above, the solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

Learn more on quadratic equation here;

brainly.com/question/8649555

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